Domain Names preg_match

[waverider303]

1. I am trying to match all subdomains of my .com to get redirected to a single folder

 

2. The input data will be $_SERVER["SERVER_NAME"]; so (*.hainymedia.com) * being anything.

So that if they goto f2hd4sak.hainymedia.com it will watch it. I am using a Switch conditional so if it find *.hainymedia.com it will redirect to the same folder.

 

I tried to use "\b[A-Z0-9._%+-]+.hainymedia.com" but I am very new to regex and I dont know what I am doing.

 

[RussellReal]

[^\.]+?\.domain.com

 

that should work

[waverider303]

didnt seem to work correctly.

[waverider303]

I get this error:

 

Warning: preg_match() [function.preg-match]: Unknown modifier '+' in /volume1/web/index.php on line 15

[RussellReal]

lolz..

 

"/^[^\.]+?\.domain.com$/"

[waverider303]

What is "/^[^\.]+?\." searching for? What I am using to get the domain is $_SERVER['SERVER_NAME']; so it will look something on these lines depending on what they type into the url:

 

hainymedia.com

www.hainymedia.com

subdomain.hainymedia.com

test.hainymedia.com

 

and I want to do a preg_match() to find *(meaning wildcard) .hainymedia.com or even just hainymedia.com (missing the leading .).

[RussellReal]

(?:[^\.]+\.)?domain.com

 

that works lolz

[cags]

If the OP wants the subdomain what on earth is the point of creating a non-capture group?

 

waverider303, can you show us a complete line of code so that we know exactly what your talking about?

[RussellReal]

cags, hes not trying to get the value hes trying to redirect all subdomains to a single folder, no use in capturing data that won't be used

 

[waverider303]

<?php
$server = $_SERVER["SERVER_NAME"];
$pattern = "(?:[^\.]+\.)?example.com";
echo "Server is: $server <br />";
switch ($server) {
case preg_match($pattern, $server):
	echo "Worked";
	break;
/*case "example.com":
	header('Location: /~root_folder');
	break;
case "www.example.com":
	header('Location: /~root_folder');
	break;*/
}
?>

 

This is what I have and i am getting "UnKnown modifier errors"

[cags]

The preg_match function uses the PCRE engine, as such the pattern requires delimiters...

 

$pattern = "#(?:[^\.]+\.)?example.com#";