post to self

[harkly]

Trying to get my form to submit to itself. However I am also trying to use an image for my submit button, when I set the type='image' it will not submit to itself. Can someone help me figure out why?

 

my button code:

<input type='submit' name='submit' value='submit' src='img/button_add.gif' width='64' height='25' class='outline' onmouseover=\"javascript:this.src='img/button_add2.gif';\" onmouseout=\"javascript:this.src='img/button_add.gif';\">

 

my if:

 

if( isset($_POST['submit']))

 

 

form:

        <form  method='post' action="<?php echo $_SERVER["PHP_SELF"]; ?>" name='mailcheck' id='form_id'>

 

 

Everything works well if I don't post to self so I can always do that.

[trq]

<form  method='post' action="" name='mailcheck' id='form_id'>

[harkly]

That doesn't work either. Works fine when type='submit' but not when type='image'

[sader]

Not sure 100% but it may be that in this case on javascript can help

 

<form name='myFormName' method='post'>

<input type='image' onclick='document.myFormName.submit()'>

</form>

[taquitosensei]

when you use type='submit'    it posts the x,y coordinates of the images.    The name plus x or y. Try a print_r($_POST) at the top of the page  with type='submit'      and you'll see what I'm talking about. 

 

 

You should check for one of those instead.  Or use a hidden field and check for it.   

 

<input type='hidden' name='submitmyform' value='true'>

for the x, y

if(isset($_POST['submitmyform_x']));    // or submitmyform_y
{
    // do whatever here 
}

for the hidden field

if($_POST['submitmyform']) { 
// do whatever here 
}

 

 

[harkly]

Thanks everyone!

 

taquitosensei's fix worked! I had no idea that it was posting my image coodinates : (

[taquitosensei]

It took a bit of hitting my head against the wall to figure that one out.

[harkly]

LOL

 

I really appreciate it!!