SIMPLE: Array variables not being passed in foreach() statement

[intech]

These foreach() statements have always thrown me for a loop...

I have a simple contact us form with a series of checkboxes where users can request notifications by different formats. They could have 1,2 or any number of boxes checked.

Here is my FORM code:

[code]
<input type="checkbox" name="some_info[]" value="Website Development" />DVD
<input type="checkbox" name="some_info[]" value="Network Solutions" />Email
<input type="checkbox" name="some_info[]" value="Computer Upgrades/Repairs" />Newsletter
[/code]

And here is my foreach() statement:

[code]
foreach($_POST['some_info'] as $some_info) {
    $info = ". $some_info .";
}[/code]

What I get in the email is only the last selection formatted like the following:

Media requested: . Newsletter .

Not all variables are being passed...

My gratitude ahead of time...

[samshel]

[code]
echo "<pre>";
print_r($_POST['some_info']);
echo "</pre>";
foreach($_POST['some_info'] as $some_info) {
    $info = ". $it_info .";
}
[/code]

try this, check if all data is posted properly or not.
hth

[intech]

my line...
[code]$info = ". $it_info .";
[/code]
Should read...
[code]$info = ". $some_info .";
[/code]

(But still same problem)

Yep all variables are printed to screen with your debug code...

[Jenk]

change the assignment operator to .= instead of just =

[intech]

Now we're getting some where...

Changed my line to the following:

[code]$info .= ". $some_info .";[/code]

It does pass all checkbox values to the email now, but I now get the dreaded error:

[quote]Notice: Undefined variable: info [/quote]

[Jenk]

add [code]$info = '';[/code] before your loop.