How to say it in php ! (if and else)

[egturnkey]

Hello friends,

 

If i have

 

$manal = "40";

 

and i wanna create random number btween 1 to 100

 

$random = rand(1, 100);

* not sure it is right or wrong for random function

 

then if we have text_1 / text_2

 

i wanna say

 

if $random >= $manal  then show text_1

 

if else ( i mean $random < $manal ) then show text_2

 

i how write it in php so can anyone fix it to me and write it 

[egturnkey]

i've tried this but gives error 

 

<?php
$manal = "40";
$random = rand(1, 100);
$text_1 ="text 1";
$text_2 ="text 2";

if  $random >= $manal {
echo "$text_1";
} else {
echo "$text_2";
}
?>

[teamatomic]

You need round brackets to contain the conditional statement:

if  ($random >= $manal)

 

 

HTH

Teamatomic

[Instigate]

I wrote this. Just a small modification.

 

<?php

$manal = "40";
$random = rand(1, 100);
$text_one = "Text One";
$text_two = "Text Two";

echo $random;
echo "\n";

if ($random>= $manal) {
  echo $text_one;
}
else {
  echo $text_two;
}
?>