send POST to external site without forms

[EchoFool]

Hey,

 

I want to know if theres a way to send links to an external site in the form of a POST without the user doing it from a form. A file host gave me their info for their API link checker and say:

 

Feel free to use the link checking API that we uses. Simply POST to *url removed* and use the following name/value pairs: id$x=$downloadid

 

Does any one understand what they are telling me to do .. im thinking CURL ? But i don't know where to start here =/

[teamatomic]

Curl or sockets.Heres a bit to get you started.

http://www.alt-php-faq.org/local/55/#id55

 

 

HTH

Teamatomic

 

[EchoFool]

Hmm okay thats confusing i have alot of questions:

 

<?php
$URL="www.mysite.com/test.php";
$ch = curl_init();   
curl_setopt($ch, CURLOPT_URL,"https://$URL"); 
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "Data1=blah&Data2=blah");curl_exec ($ch);    
curl_close ($ch);
?>

 

If i use CURL where do i get the return values =/ And if it returns a number of different values how do i know how to grab them :S This just seems to be doing an "include" rather than a way to return the values that im checking ?

[teamatomic]

You get it from curl the same way you get a page. All you are doing is submitting a request and waiting for the results, you are just passing a bit more than a simple request, thats all.

 

 

HTH

Teamatomic

[EchoFool]

Well i put this:

 

<?php
ForEach ($arr2 AS $Value){
$arr3 = str_split($var, 30); //cut off the url so it only has the ID in array[1]
$ch = curl_init();   
curl_setopt($ch, CURLOPT_URL,"removed from post"); 
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "id$x=".$arr3[1]."");
curl_exec ($ch);
curl_close ($ch);


Echo $Value.'<br>';
$var2 = $var2+ 1;
}
?>

 

Now the company told me this:

The script will return name, site, size and status. Status is 0 for OK, 2 for expired and 3 for temporarily unavailable.

 

But currently how do i get the return values from the above =/ because at the moment i don't have the returned values for me to use in my script ?

[teamatomic]

You have to ask curl to give you something.

$result=curl_exec ($ch);

var_dump()$result);

also, where does $x come from? you dont show it in the code posted.

 

 

HTH

Teamatomic

[EchoFool]

I equally have no idea the info i was given by them said :

 

Feel free to use the link checking API that we uses. Simply POST to *url removed* and use the following name/value pairs: id$x=$downloadid

 

I am merely guessing the POST name is id$x and thus $x is not a variable but just a string =/ Currently i just get a return value of 1 , don't know if thats my issue or at their end so im awaiting a reply from them on more info that can aide in this problem.

[teamatomic]

No, $x is an integer, no one that writes an api would have id$x as it would cause a lot of problems in the processing.

 

 

HTH

Teamatomic