Replace text using php

[leachus2002]

Hi There,

 

I am developing an internal web page on our intranet - and I am using the $_SERVER['REMOTE_USER'] varible to pass through who is logged on to a particular web page. Unfortunaetly, if I echo this on to the screen, it displays "domainname/username" - is there any way that I can remove the "domainname/" from the start of the string so that it just echo's "username"?

 

Help appreciated

 

Thanks

Matt

[oni-kun]

str_replace:

$result = "domainname/username";
$username = str_replace("domainname/", "", $result);
print $username;

 

explode (preferred)

$result = "domainname/username";
$username = explode("/", $result);
print $username[1];

[leachus2002]

Thanks for coming back to me, however, I think I am getting confused:

 

Where I am using the "$_SERVER['REMOTE_USER']" varible, would i have to code the following:

 

$result = "
$_SERVER['REMOTE_USER']";
$username = explode("/", $result);
print $username[1];

 

Because the user will always be different

 

Thanks

 

Matt

[oni-kun]

Almost, This should work:

$result = $_SERVER['REMOTE_USER'];
$username = explode("/", $result);
print $username[1];

[leachus2002]

Hi,

 

Doesnt look like it I am afraid - I am just getting blank on both print $username[1] and I even tried echo $username.

 

But if I echo $_SERVER['REMOTE_USER'] - I get domainname\username

 

Any ideas?

[oni-kun]

The slash is reversed, as you see. That is simple to amend.

$result = $_SERVER['REMOTE_USER'];
$username = explode("\\", $result);
print $username[1];

 

[ot]no salathe it doesn't need regex.[/ot]

[leachus2002]

Ah totally pefect!

 

Sorry that was my mistake initially!

 

Brilliant work - thank you!

[leachus2002]

Sorry to be a pain - but is there any way I can get that print line in to a varible? I have tried $user = print username[1]; echo $user - but that will echo username1

 

Thanks

Matt

[oni-kun]

Sorry to be a pain - but is there any way I can get that print line in to a varible? I have tried $user = print username[1]; echo $user - but that will echo username1

 

Thanks

Matt

 

You'd need to do echo $username[1]. Echo and print are pretty much the same thing.