Tiny syntax explanation

[bobicles2]

if($login != '')

 

what is this saying? its the last part im unsure about

 

thanks in advance

rob

 

[papaface]

I means if the variable $login does not contain any text then to perform a section of code.

[bobicles2]

I means if the variable $login does not contain any text then to perform a section of code.

 

How would this have any reference to this script though, because if the login field which is defined as $login has no text, then it has nothing to look up in the database and compare against (as the script below is designed to checked for duplicate log in names)

 

if($login != '') {
	$qry = "SELECT * FROM members WHERE login='$login'";
	$result = mysql_query($qry);
	if($result) {
		if(mysql_num_rows($result) > 0) {
			$errmsg_arr[] = 'Login ID already in use';
			$errflag = true;
		}
		@mysql_free_result($result);
	}
	else {
		die("Query failed");
	}

 

[Pikachu2000]

I means if the variable $login does not contain any text then to perform a section of code.

 

Actually, it's saying if the variable does not NOT contain any text, then perform the code. It's essentially the same as if( !empty($login) )

[bobicles2]

I means if the variable $login does not contain any text then to perform a section of code.

 

Actually, it's saying if the variable does not NOT contain any text, then perform the code. It's essentially the same as if( !empty($login) )

 

now it makes perfect sense, so long as the field has an entry, we check the database for multiple entries

 

thanks man!