Rawns Posted September 7, 2006 Share Posted September 7, 2006 I've created a simple link directory on my site (http://www.paulrawnsley.com/links.php) but cant figure out ho to make the 'link' entrys display as clickable links. Can anyone help?this is the code to show the directory: [code]<?php import_request_variables('p'); $user="XXXXXXX"; $pass="XXXXXXX"; $db="linkdb"; $link=mysql_connect("sql02",$user,$pass); if (!$link) die ("Couldn't connect to MySQL server"); mysql_select_db($db,$link) or die("Couldn't connect to $db".mysql_error()); $query="SELECT * FROM linkdb ORDER BY `title` ASC"; $result=mysql_query($query,$link); print"<table align='center' width='100%' cellpadding='2' cellspacing='2' border='0'>"; print"<tr bgcolor='#b3cac5'>"; print"<font size='3'>"; print"<th>Title</th>"; print"<th>Link</th>"; print"<th>Description</th>"; print"</font>"; print"<tr>"; while ($row=mysql_fetch_row($result)) { print"<tr>"; foreach($row as $field) print"<td>$field</td>"; print"</tr>"; } print"</table>";?>[/code] Quote Link to comment Share on other sites More sharing options...
obsidian Posted September 7, 2006 Share Posted September 7, 2006 where you're using your foreach() to loop through your row, you'll need to adjust it to allow you to pull out the column for "link" and echo it slightly differently. let's say your column name for the actual link is simply "link", you could do something like this:[code]<?phpwhile ($row = mysql_fetch_array($result)) { echo "<tr>\n"; foreach ($row as $key => $val) { // now, let's see if it's the "link" column and show a link if it is if ($key == 'link') echo "<td><a href=\"$val\">$val</a></td>\n"; else echo "<td>$val</td>\n"; } echo "</tr>\n";}?>[/code]hope this helps Quote Link to comment Share on other sites More sharing options...
Rawns Posted September 7, 2006 Author Share Posted September 7, 2006 Its kind-of helped. The text does link but its messed the table up big time... Quote Link to comment Share on other sites More sharing options...
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