PHP YYYY to YY confused

[monkeytooth]

Ok I have a 4 digit year stored in a database column.. I pull it out from the DB and I try to convert it to a 2 digit year. Which at first I thought was working fine.. Then i realized im only returning the current year. in 2 digit format.

 

I though going the route of:

$semister_year= date('y', strtotime($bcinfo1[0]['semister_year']));

would do me some justice but its not

$bcinfo1[0]['semister_year']

Is the year.. coming from the DB.. any ideas? The years range I just want the two last digits..

 

example 2012 to 12

[Mchl]

strtotime can't convert just a year to timestamp. It needs full date at least.

 

Anyway, keep it simple.

 

$semister_year = substr($bcinfo1[0]['semister_year'],2,2)

[kenrbnsn]

The string "2012" is not a valid date to the strtotime() function. Just add the string "-01-01" to it and it will work:

<?php
$semister_year= date('y', strtotime($bcinfo1[0]['semister_year']) . '-01-01');
?>

 

Ken

[monkeytooth]

substr, why didnt I think of that.. oi. Thank you for putting that in perspective :-)

 

but both valid concepts.. thank you both.

[Mchl]

Actually, 2012 for strtotime means 'today 8:12pm'

[PFMaBiSmAd]

$semister_year = $bcinfo1[0]['semister_year'][2] . $bcinfo1[0]['semister_year'][3];