SquattingDog Posted May 11, 2010 Share Posted May 11, 2010 Hi guys, I have been lurking for a while, but this is my first post, as although I have read virtually every other thread which has the same issue (google-searched, as well as forum-searched), I cannot seem to resolve it. I am getting "Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\EMS\stockList.php" from the following on line 79 (the mysql_fetch_array line), and have included the code directly referenced to it: $_POST['catName'] is working, as I have tried echoing it before and after, and in this instance, you can replace it with <variable>. PHP Version is 5.3.0, running on WAMP 2.0 on Vista X64. Deployation environment runs it on Win XP 32-bit (with MUCH better performance than I experience from WAMP on Vista X64). 77 $query = 'INSERT INTO `EMS`.`EMSCat` (`catID`, `category`, `shortcat`, `desc`) VALUES (NULL, \'' . $_POST['catName'] . '\', \'\', \'\');'; 78 $catQuery = mysql_query($query) or die(mysql_error()); 79 $catResult = mysql_fetch_array($catQuery); 80 $querySelect = 'SELECT `EMSCat`.`catID` FROM `EMS`.`EMSCat` WHERE `EMSCat`.`category` = \'' . $_POST['catName'] .'\''; 81 $queryQuery = mysql_query($querySelect) or die(mysql_error()); 82 $queryResult = mysql_fetch_array($queryQuery); 83 $cattyID = ($queryResult['catID']); 84 $queryTwo = 'INSERT INTO `EMS`.`EMSSubCat` (`catID`,`subcatID`,`subCat`,`desc`) VALUES (\'' . $cattyID . '\' , \'\' , \'' . $_POST['subcatName'] . '\',\'\');'; 85 $queryTwoArray = mysql_query($queryTwo) or die(mysql_error()); 86 87 //GET CATEGORY ID 88 $query = 'SELECT * FROM `EMS`.`EMSCat` LEFT JOIN `EMS`.`EMSSubCat` ON `EMSCat`.`catID` WHERE `EMSCat`.`category` = \'' . $_POST['catName'] . '\' AND `EMSSubCat`.`subCat` = \'' . $_POST['subcatName'] . '\''; 89 $result=mysql_query($query) or die(mysql_error()); 90 $row = mysql_fetch_array($result); 91 $catID=$row['catID']; 92 $subcatID = $row['subcatID']; Things I have tried: Changing the permissions, username, password and IP for connecting - connection is fine, same issue arises. Adding a new call/manual connection before the query, again connection is fine, same issue arises. Changing quotation marks to double quotes, and removing quotes wherever possible, as I was able to get this to work using phpMyAdmin when using no escaping of quotation marks - but this doesn't work on the actual code and also gave me '' . <variable> . '' in the database, instead of just <variable>. Further information: Despite this error, the `category` gets inserted into the database, and the `subCat` information gets inserted. I can post the whole lot of the code, if required. Things which have changed: data in the EMSItem table has changed (different supplier), but is being imported with no single or double-quotes, and thus should not be affecting this. I need this up and running asap, as I have already spent two weeks trying to resolve this to no avail! Any help is greatly appreciated! PS: I am a relative noob to PHP/MySQL, and have had to take this over from my previous business partner who is no longer in the business. Link to comment https://forums.phpfreaks.com/topic/201322-mysql-error-where-there-was-never-one-before/ Share on other sites More sharing options...
DavidAM Posted May 11, 2010 Share Posted May 11, 2010 77 $query = 'INSERT INTO `EMS`.`EMSCat` (`catID`, `category`, `shortcat`, `desc`) VALUES (NULL, \'' . $_POST['catName'] . '\', \'\', \'\');'; 78 $catQuery = mysql_query($query) or die(mysql_error()); 79 $catResult = mysql_fetch_array($catQuery); In line 79, $catQuery is the result of executing an INSERT statement. The mysql_query() function returns a boolean in this case (true or false). There are no rows to fetch so you should not be calling mysql_fetch_array() here. Link to comment https://forums.phpfreaks.com/topic/201322-mysql-error-where-there-was-never-one-before/#findComment-1056214 Share on other sites More sharing options...
SquattingDog Posted May 11, 2010 Author Share Posted May 11, 2010 Outstanding, thank you - it's always the simple things . There was NO need for me to be fetching anything, and this explains why it was running fine. Thank you again for your (super-fast) help! Link to comment https://forums.phpfreaks.com/topic/201322-mysql-error-where-there-was-never-one-before/#findComment-1056215 Share on other sites More sharing options...
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