havenpets Posted May 22, 2010 Share Posted May 22, 2010 Okay, so I am creating a Jquery registration page using "dialog". I am using the "jquery" version of AJAX. It's pretty similar, and the problem I am having can happen to either. Basically this is how my code is organized: function go_ajax(formtype){ formvalue = document.getElementById(formtype).value; $.get("/xatron/check.php?type="+formtype+"&value="+escape(formvalue), function(data) { // TEST alert(data); return data; }); } Data = httpObject.responseText Thats the same as a "get" script in AJAX. Now, later in my code I have... if(go_ajax('username') == 0){ // Fail }else{ // Pass } Now, it will come up as "Pass" EVERYTIME because... go_ajax('username') = undefined. But when I do the test and do the alert above it presents to me, 0 or 1. x_X And it alerts AFTER undefined alerts. How would I go about fixing this? Anyone know? (p.s. YES, I know this is jquery BUT ajax is the exact same problem (i've tried both methods). Thank you, Matt Link to comment https://forums.phpfreaks.com/topic/202576-ajax-returns-undefined/ Share on other sites More sharing options...
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