Return Function as array?

[EchoFool]

Hey,

 

I am trying to return my function without assigning it to a variable so i can use it in an if statement but it seems to be syntax'd incorrectly - what i am trying to do is this:

 

<?php
function catexists($RecordID){
$Get = mysql_query("SELECT Count(RecordID) AS ID,StaffPost,StaffView FROM catergories WHERE RecordID='".SQLskip($RecordID)."'") or die(mysql_error());
$row = mysql_fetch_assoc($Get);
return array($row['ID'],$row['StaffPost'],$row['StaffView']);
}

If(isset($_GET['cat']) && catexists($_GET['cat'])[0] == 1){
//display position 0 of array here
}
?>

 

But the error i get is :

 

Parse error:  syntax error, unexpected '[' in  on line 18

 

Yet it is in an array so i don't see why it won't work, but i cant assign a variable for the if statement either. Unless i can do it "in" the if statememnt?

[kenrbnsn]

I don't believe you can do this in PHP and have to use a variable:

<?php
if (isset($_GET['cat'])) {
   $tmp = catexists($_GET['cat']);
   if ($tmp[0] == 1) {
//
//  etc...
//
   }
}
?>

 

Ken

[EchoFool]

Damn thats a shame but ill have to use two IF's then lets hope future PHP versions support it

[PFMaBiSmAd]

Given that your function executes a query and returns more than one value and that you are then going to want to access those other values inside the conditional logic, you likely would not want it to work the way you tried as you would then be calling the function multiple times. That would not be very kind to your database server, i.e. executing the query each time you referenced any element of catexists($_GET['cat'])[x].

[EchoFool]

Thats a good point Didn't think of that.