RegExp confused

[robert_gsfame]

How can i show the alert once text doesn't consist of number and alphabet using RegExp?

thx

[Adam]

var str = '££$%£';

if (str.match(/^[^a-zA-Z0-9]+$/))
{
    alert("doesn't contain alphanumeric");
}

[robert_gsfame]

what i want is a text must consist of a combination of letter and number....if one missing then alert(),

[Adam]

Yeah?

 

var str = '££$%£';

if (str.match(/^[^a-zA-Z0-9]+$/))
{
    alert("this field must contain only alphanumerical characters");
}

[robert_gsfame]

there is nothing to do with alphanumeric....i just want to check that a text must at least has both number and letter...therefore it is also allowed to have special characters in the text

[Adam]

Well perhaps you should be clearer in future? You're English isn't exactly perfect.

 

Anyway, first idea that comes to mind:

 

var str = '£$ewe£$1556£$%£';

if (!str.match(/([a-z].*[0-9]|[0-9].*[a-z])$/i))
{
    alert("this field must contain at least 1 number and 1 letter");
}

[robert_gsfame]

Thx so much mr Adam.....it works perfect!!!!

what is actually the last part of the pattern used for $/i

can give me some short explanation ? :P

 

[Adam]

Actually I didn't mean to leave the $ in there, that matches the end of the string - you'll want to remove that. The "i" on the outside of the delimiters is the case-insensitive modifier, basically means the same as:

 

/([a-zA-Z].*[0-9]|[0-9].*[a-zA-Z])/

[robert_gsfame]

:D okay! again thx for your help!!!