for() problem - should show all results

[firedealer]

Below the PHP code will show the first record only. If I replace $chunks in for() to the true number which is 5, it will show two records.  I need $chunks to be there for customize from $_POST.  Any solution?  Thanks.

 

<?php
// Retrieve from $_POST which isn't included in this code for now.
$word = "applesauce";
$number = 5;

$chunks = ceil(strlen($word)/$number);

echo "The $number-letter chunks of '$word' are:<br />\n";
for ($i=0; $i < $chunks; $i++) {
$chunks = substr($word, $i*$number, $number);
printf("%d: %s<br />\n", $i+1, $chunks);
}
?>

[mrMarcus]

printf("%d: %s<br />\n", $i+1, $chunks);

 

$i+1 is incrementing $i by 1 causing your for() loop condition of $i < $chunks to complete on the first pass.

[firedealer]

Your comment doesn't make a sense to me.  Can you post a solution code to enlighten me?

[kenrbnsn]

You're reusing the variable $chunks inside the for loop. Use a different variable.

 

Ken

[mrMarcus]

Yes, my head was somewhere else.

 

You're reassigning $chunks within the loop.

 

$word = "applesauce";
$number = 5;

$chunks = ceil(strlen($word)/$number);

echo "The {$number}-letter {$chunks} of '{$word}' are:<br />\n";
for ($i=0; $i < $chunks; $i++) {
$chunks2 = substr($word, $i*$number, $number);
printf("%d: %s<br />\n", $i+1, $chunks2);
}

[firedealer]

Thanks for a solution code.  Here mine is:

<?php
$word = "applesauce";
$number = 5;
$calc = ceil(strlen($word)/$number);
$howmany = $calc;
$chunks = $calc;

echo "The $number-letter chunks of '$word' are:<br />\n";
for ($i=0; $i < $howmany; $i++) {
$chunks = substr($word, $i*$number, $number);
printf("%d: %s<br />\n", $i+1, $chunks);
}