Detecting if you are watching a picture or a picture in a <img /> code

[Third]

Hi!

Im using a php-file to put out a jpg header. It gathers the data from an image gallery database via mysql.

 

The problem is, I want it to load two different versions of it.

 

One version is what you see when i call the <img src='photo.php&id=50' />, the picture in the img tag on one page,

and the other version is if you clicked my direct link to the picture.

 

Is there some way i can find out if the photo.php is a part of another web-page, like if it it was included on gallery.php

and if photo.php is viewing only the jpg?

 

the photo.php is getting data from my database and results in something like:

 

header('Content-type: image/png');

$im = imagecreatefromjpeg($imglink);

imagejpeg($im);

imagedestroy($im);

 

I've tried to make some workarounds, like in gallery.php to set a variable and

trying to read it in photo.php, (wich would not be made if you just visited photo.php)

but it didnt work out. I just get the same results in both.

 

I want to show the pic in a img tag without any watermarks, and if the user goes to the photo via photo.php,

it adds the watermark..

 

I hope you understand my question and how I do this

 

[mentalist]

I'm not a hundred percent clear exactly what your after but...

 

At the point of image generation / inclusion, you should know which image it should be!

So, you generate the image accordingly, either by calling another script or using GET / POST:

header('Content-type: image/png');
if(isset($_GET['mark'])){$im = imagecreatefromjpeg($imglink);}
else{$im = gen_image();}
imagejpeg($im);
imagedestroy($im);

 

To decide depending on where it came from you can use $_SERVER['HTTP_REFERER'], but it might not always be set.

 

For protection you could do similar to when doing CAPTCHA's, generate a ref in the db, the image page reads the ref to see if still valid, etc...

 

 

I hope something helped because still unsure... lol

[Third]

Try to see it like this. I want a script that can detect if you are either:

 

1. Seeing the picture in a webpage, by using <img src='thatimage' />

 

and

 

2. If you right click that image in the webpage, and chose View Image, it opens only the image and I want to detect this from 1.

 

So basically, when im showing the picture using <img>, i want it to show without watermark. If user clicks the image to see it in full screen in the browser, i want watermark on it.

 

What I have done now is that im showing the image using the direct link for the image in the <img>.. like src='/bla/folder/file.jpg'

and i have that <img> in a href link to a php script that generates that picture, with a water mark.

 

You can see here: http://nesthus.net/photo/263

 

if i include that php script on that page, in the <img src=', i will have watermarks on the picture there wich is unwanted.

 

Thanks for trying!

[mentalist]

As said, their in different locations, do it from within the image script.

 

try... 'REQUEST_URI' or 'SCRIPT_NAME' or something... if its in the largeImage directory then do your thing...

[phpchamps]

why dont you add a parameter in the image src.. like

 

<img src='filename/id/fromimagesource' />

 

and when you get it on the file.. check for that parameter.. if it is there do not add watermark.. if it is not.. then only add watermark