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Hi guys,

 

I'm a bit stuck here. I've got it mostly working but can't complete my next task. Basically, I have a table where each user has 3 fields and each field has a value.

 

eg

user_id | field_id | value
1           |      1     |   UK
1           |      2     |   Yes
1           |      3     |   1
2           |      1     |   USA
2           |      2     |   Yes
2           |      3     |   4

 

I'm trying to count users who match a few conditions. In order to count as 1, the user must be from the country specified in my loop and have a field_id 2 = Yes and field_id = specified by the loop again.

 

This is what I have so far - it counts just by country which is promising but I don't know how to make a conditional mysql statement where if all 3 fields (country, yes, ID) = the specified reference OR country and yes are true.

 

It must prefer the 3 statements being true, then if the 2 are true... (in other words, if either statement is true, count = 1). Here is what I have so far:

 

$sql = "SELECT COUNT(*) FROM `fields_values` AS tab1, `fields_values` AS tab2, `values` AS tab3, `fields_values` AS tab4
WHERE tab1.user_id = tab2.user_id
AND tab2.user_id = tab3.user_id
AND tab3.user_id = tab4.user_id
AND (tab1.field_id = 11 AND tab1.value = '$item->website')
AND (tab2.field_id = 16 AND tab2.value= 'Yes')
AND (tab3.field_id = 17 AND tab3.value= '$item->id')
AND (tab4.field_id = 18 AND tab4.value>='$date_first' AND tab4.value<='$date_last')";

 

Thanks for the help!

 

RJP1

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