Warning: mysql_affected_rows(): supplied argument is not a valid MySQL-Link reso

[BradD]

Hey Guys;

 

I can't figure out this error;

 

Warning: mysql_affected_rows(): supplied argument is not a valid MySQL-Link resource in /home/database/public_html/db_insert.php on line 20

 

The Table is being Updated when the form is submitted but this error message is also...

using the mysql_affected_rows()

 

if( mysql_affected_rows($query) == 1 )  {
$id = mysql_insert_id();
$new_record = "SELECT `firstname`, `username`, `email`, `emailactivated` FROM `members` WHERE `id` = $id";
$result = mysql_query($new_record);
$array = mysql_fetch_assoc($result);

 

Here's how I see it, blurry and probably wrong but...

 

We are using the mysql_affected_rows function to discover whether data in the $query Variable has been recorded, then we are assigning a variable $new_record to the SELECT function, we then tell $new_record mysql_query that it is now $result and then we fetch this $result from the $array. That's probably the shortest possible explanation and probably wrong as well.

 

Anyway I can't figure out whats causing this error? Because I'm pretty sure  the link resource is okay.

 

<?php


require_once('connectDB.php'); 

$password = md5($_POST['password']); // hash the password before the array_map()

array_map('mysql_real_escape_string', $_POST); // Since only one element won't need to be sanitized, run the entire $_POST array through mysql_real_escape_string.

$conf_code = md5(uniqid(rand(), true)); // generates confirmation code to use wth the confirmation email that gets sent //

$query = "INSERT INTO `members` (
`firstname`, `lastname`, `username`, `password`, `accounttype`, `country`, `state`, `city`, `phone`, `mobile`, `business`, `email`, `website`, `signupdate`, `emailactivated`, `confirmed`
) VALUES (
'" . $_POST['firstname'] . "', '" . $_POST['lastname'] . "', '" . $_POST['username'] . "', '" . $password . "', '" . $_POST['accounttype'] . "', '" . $_POST['country'] . "', '" . $_POST['state'] . "', '" . $_POST['city'] . "', '" . $_POST['phone'] . "', '" . $_POST['mobile'] . "', '" . $_POST['business'] . "', '" . $_POST['email'] . "',  '" . $_POST['website'] . "', now(), '" . $conf_code . "', 0
)";
mysql_query($query) or die("There has been a system problem. Failed to add record to database.");

if( mysql_affected_rows($query) == 1 )  {
$id = mysql_insert_id();
$new_record = "SELECT `firstname`, `username`, `email`, `emailactivated` FROM `members` WHERE `id` = $id";
$result = mysql_query($new_record);
$array = mysql_fetch_assoc($result);

$email = $array['email'];
$subject = "Your confirmation code from the website";
$message = "Dear " . $array['firstname'] . ",\r\n";
$message .= "Thank you for registering at my website. To confirm your registration, please visit the link provided and enter the following confirmation code,\r\n";
$message .= $array['emailactivated'];
$from = "From: brad@mlmnetworkingsystem.com\n";

if( mail($email, $subject, $message, $from) ) {
header('Location: nuttin.php'); // redirects to a "landing page" if mail was sent successfully.
exit(); // stops further script execution after redirect.
}
}
?>

 

 

 

 

[kenrbnsn]

You need to use the result of the mysql_query() function call in the mysql_affected_rows() function call, you're using the $query itself.

 

<?php
$rs = mysql_query($query) or die("There has been a system problem. Failed to add record to database.");

if( mysql_affected_rows($rs) == 1 )  {
?>

 

Ken

[PFMaBiSmAd]

The key to effectively using any function in programming is to read the documentation for that function, especially if you get an error when you use that function -

Description

int mysql_affected_rows ([ resource $link_identifier ] )

Get the number of affected rows by the last INSERT, UPDATE, REPLACE or DELETE query associated with link_identifier .

 

Parameters

 

link_identifier

The MySQL connection. If the link identifier is not specified, the last link opened by mysql_connect() is assumed. If no such link is found, it will try to create one as if mysql_connect() was called with no arguments. If no connection is found or established, an E_WARNING level error is generated.

 

mysql_affected_rows() (optionally) accepts the connection link identifier as a parameter.

 

[BradD]

Thanks man, I'll have a crack at it...

 

You need to use the result of the mysql_query() function call in the mysql_affected_rows() function call, you're using the $query itself.

 

<?php
$rs = mysql_query($query) or die("There has been a system problem. Failed to add record to database.");

if( mysql_affected_rows($rs) == 1 )  {
?>

 

Ken

[kenrbnsn]

Don't try my solution, it's wrong. Look at PFMaBiSmAd's reply.

 

Ken

[BradD]

No probs, I gave it a try and learned something along the way, learned it didn't work 

 

I'm still trying to figure it out...

 

Don't try my solution, it's wrong. Look at PFMaBiSmAd's reply.

 

Ken