Using OR/AND in preg_replace ?

[dominod]

Hi

 

I want to use two lines for on string in preg_replace..

 

I want the following two codes to work:

 

$shop = preg_replace('/:([a-zA-Z0-9]*(\s){0,1})/','',$search);

 

$shop = preg_replace('/: ([a-zA-Z0-9]*(\s){0,1})/','',$search);

 

The difference between them is that the second one got space between ":" and "([a.."..

 

The problem I am trying to solve is this..

 

When I use the first line of code and type in "keyword: wordkey" it echo "keywordwordkey" instead of "keyword" as it shuld and does when I enter "keyword:wordkey" (without the space).

 

When I am using the other line of code and type in "keyword:wordkey"  it echo "keyword:wordkey" and not "keyword" is it shuld and does when I enter "keyword: wordkey" (with the space).

 

What I want is that it echos "keyword" no matter if there is a space there or not ..

 

Does anyone know how to fix this?

 

Thanks in advance

[dominod]

Problem solved like this:

$shop = preg_replace('/:(\s*)([a-zA-Z0-9]*(\s){0,1})/','',$search);