convert arrays values to string

[playwright]

hello!! is there any function that can convert every single value of an array into string??? I tried implode() but i think it converts the whole array into one string..maybe i'm wrong..this is what i'm trying to do..

 

preg_match_all('/<img src\=[\"](.*?)[\"] (.*?)>/si',$x, $y);

$count = count($y;

for ($i=1;$i<=$count;$i++){

$keys = implode("+",$y[$i]);

$new = substr($keys,30,7);

}

 

any ideas??

[kenrbnsn]

Can you give us an example of the input and the results you want?

 

Ken

[bh]

heres the problem:

 

$keys = implode("+",$y[$i]);
$new = substr($keys,30,7);

 

$keys is an array...

so concate $keys elements

 

simple example:

$keys = implode("+",$y[$i]);

$str = '';
foreach ($keys as $key)
{
$str .= $key;
}

$new = substr($str,30,7);

[kenrbnsn]

Do you want

<?php
$str - implode('',$y[$i]);
?>

 

I'm still not seeing what you're trying to do.

 

Ken

[playwright]

I want to create a table $y that contains anything that matches with the pattern /<img src\=[\"](.*?)[\"] (.*?)>/si'..Then convert any value of the table into string so as to check if the value contains a specific phrase..That's way i'm using substr().

[playwright]

  Quote

heres the problem:

 

$keys = implode("+",$y[$i]);
$new = substr($keys,30,7);

 

$keys is an array...

so concate $keys elements

 

simple example:

$keys = implode("+",$y[$i]);

$str = '';
foreach ($keys as $key)
{
$str .= $key;
}

$new = substr($str,30,7);

 

it gives me an error Invalid argument supplied for foreach()..

[kenrbnsn]

So, I tried this example:

<?php
$x = '<img src="x.jpg" width=1 height="1">';
preg_match_all('/<img src\=[\"](.*?)[\"] (.*?)>/si',$x, $y);
?>

Which results in $y containing:

Array
(
    [0] => Array
        (
            [0] => <img src="x.jpg" width=1 height="1">
        )

    [1] => Array
        (
            [0] => x.jpg
        )

    [2] => Array
        (
            [0] => width=1 height="1"
        )

)

 

Please explain using the above output what you're trying to obtain.

 

Ken

[bh]

@kenrbnsn: and i dont understand this:

$new = substr($keys,30,7);

why the fix 30 whether ?

 

@playwright: you should specify the task.

[playwright]

I'll be more specific : i Want to grab every :

<img src="blablabla" border="X" alt="" title="X" class="X" /> that exists in the source code..That's why i use preg_match_all(). Then i want to check for every record if in "blablabla" a specific word is contained.Let's say if "smilies" is contained in "blablabla". And "smileys" appears only in 30th position of "blablabla" and that's why i use substr()..

[bh]

Then why dont you get only the images src's contain?

[playwright]

Which pattern should i use to do so??

[playwright]

Problem solved..I just needed to use

foreach ($y[$i] as $img){}..