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HI I'm kinda new to PHP Mysql, so I Dont really know how to define my problem properly to search for a solution.

So far I have only found Solutions to update and Insert, 

I am  having some problems sending data across to a different page.

I am looking for a solution without using a onscreen button to submit tha data. I would like to send the data across via Href ( either javascript Submit or just a  Href link)

I have included both in my code.

So if you could please point me in the right direction and inform me where i am going wrong that would br great.

thank you In advance btw.

///////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

FirstPageCode.php

<form name="MyTable" method="POST">

 

<script type="text/javascript">

function submitMe()

{

document.MyTable.action="http://localhost/CI/Buy.php?ID=<?=$ID?>";

//document.MyTable.target="targetName";

document.MyTable.value="Send";

document.MyTable.submit();

return;

}

 

//$PostID = $_POST["PostID"];

 

mysql_connect('localhost', 'root', 'spe11gard');

@mysql_select_db(CI) or die( "Unable to select database");

$QueryQ="SELECT * FROM MyTable where ID";

//$QueryQ="SELECT * FROM MyTable where ID LIKE '%$PostID%'";

$ResultR=mysql_query($QueryQ);//30

$onN=mysql_numrows($ResultR);

 

mysql_close();

 

echo "<b><center>on Smiths</center></b><br><br>";

?>

 

    <table class="striped">

        <tr class="header">

            <td> Name </td>

            <td>zero    </td>

            <td>one      </td>

            <td>two      </td>

            <td>three      </td>

            <td>four        </td>

 

        </tr>

<?php //50

$i=0;

 

while ($row = mysql_fetch_array($ResultR))

{

$ID=$row['ID'];

$zero=$row['zero'];

$one=$row['one'];//60

$two=$row['two'];

$three=$row['three'];

$four=$row['four'];

 

echo "<tr>";

echo "<td>$ID      </td>";

echo "<td>$zero    </td>";

echo "<td>$one        </td>";

echo "<td>$two        </td>";

echo "<td>$three        </td>";

echo "<td>$four GP      </td>";

echo '<td> <a href="http://localhost/CI/Buy.php?ID=<?=$ID?>"> <i>Buy</i></a>      </td>';

echo '<td> <a href=javascript:this.submitMe();><i>Buy</i></a> </td>';

echo "</tr>";

$i++;

}

?>

    </table>

</form>

 

 

///////////////////////////////////////////////////////////////////////////////////////////////

SecongPageCode.php

<?php

if (isset($_POST['$ID']))

{

//$ID = $_REQUEST['ID'];

echo "ID: $ID ";

}

?>

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https://forums.phpfreaks.com/topic/208084-_post-_get-_request-problem/
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thanks again for the pointers, I have tried using $_get  and $_request, the secondpage still comes up blank?  I think the data is not being sent across, though I am not sure where the problem is in the First page.

What is the url you're using when going to the secound page? I am assuming you're url is something like http://localhost/CI/Buy.php?ID=123 (where 123 corresponds to a row in your database)

 

In Buy.php you should be able to use

if(isset($_GET['ID'])) {
    echo 'ID is: ' . $_GET['ID'];
}

Which should output something like

ID is: 123

dreamwest & wildteen88

Thank you so much, I really appreciate your help.

The problem was I was using $_post where I shoud be using $_get or $_request in buy.php

2nd Problem was the 'ID is: 123' was not seen within my Echo href ......... I was seeing ID=?<?$ID?>

Problem solved, I was not sending properly and not recieveing properly.

 

?>

<td> <a href="http://localhost/CI/Buy.php?ID= <?=$ID?> "> <i>Buy</i></a>      </td>

<?; 

 

<?php

if (isset($_GET['ID']))

{

echo "<BR>ID: $ID";

echo '<BR>ID is: ' .$_GET['ID'];

}

?>

Have a

:D :D

each!

 

thanks again

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