johnsmith153 Posted July 28, 2010 Share Posted July 28, 2010 Ok it's not that complex but has got me. SELECT ((ACOS(SIN(".$lat." * PI() / 180) * SIN(`lat` * PI() / 180) + COS(".$lat." * PI() / 180) * COS(`lat` * PI() / 180) * COS((".$long." - `long`) * PI() / 180)) * 180 / PI()) * 60 * 1.1515) AS `distance` FROM `users` etc.... The above is for working out lat/long values. However I need to adust the above to return ALL fields from the table. I know * will do it but how would I incorporate the extra stuff that I have? There are 20/30 fields and I have just taken over the code so can't be 100% exactly which fields need pulling so must pull all. Quote Link to comment Share on other sites More sharing options...
Pikachu2000 Posted July 28, 2010 Share Posted July 28, 2010 Then you need to list them all explicitly, which you should always do anyhow. Quote Link to comment Share on other sites More sharing options...
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