displaying input box with select in loop

[mraza]

hi i am in situation to display input box along with select option , here is my code

<?php
$run= $dbc->db("SELECT * FROM `table` WHERE `id`='$id'");
?>
<select name="service">
<?php while ($result = mysql_fetch_array($run)) { ?>
<option value="<?php echo $result['id'] ; ?>"><?php echo $result['service'] ; ?></option>
<?php  // This is problem i need to get this as hidden field but it breaks my select options. ?>
<input type="hidden" value="<?php echo $result['data'] ; ?>" name="data" />
<?php 	} ?>
</select>

 

so here i am stuck

<input type="hidden" value="<?php echo $result['id'] ; ?>" name="data" />

 

when i repeat in while loop it breaks options box and display other options without in select box. any help please thanks

[JasonLewis]

Try storing the hidden fields in an array, then imploding them after you close the select box.

 

<?php
$run = $dbc->db("SELECT * FROM `table` WHERE `id`='$id'");
?>
<select name="service">
<?php 
$hidden = array();
while ($result = mysql_fetch_array($run)) { 
?>
<option value="<?php echo $result['id'] ; ?>"><?php echo $result['service'] ; ?></option>
<?php
	$hidden[] = '<input type="hidden" value="'. $result['data'] . '" name="data" />';
} 
?>
</select>
<?php echo implode("\n", $hidden); ?>

[mraza]

Thank you very much sir for your help. its solved