Model application form

[emediastudios]

Hi Everyone.

I am in need of assistance,

I need a form that i will use on a model agency site i am making, the form i have only has the option to upload one image and records name, age etc... What i need is a form that will upload multiple images, 2 will do but if i had a option to add more that would be great, and a pdf resume, does anyone have a similar form i can have a look at that does this, any help be awesome, i am already over the deadline.

[Wolphie]

http://www.devarticles.com/c/a/PHP/Creating-a-MultiFile-Upload-Script-in-PHP/

[emediastudios]

Thanks, i read that.

Still didn't help, i kind of need one that will upload 2 images and a pdf, as well as put the record in the database, i have name, age, phone ect to go in the form too, thanks anyway

[trq]

Sounds like your fishing for someone to write the code for you instead of learning from examples. That's not the point of this board.

 

Post your request in the freelance board after you've read the stickies.

[emediastudios]

This what i have, i just need help getting the second image to upload.

I am unsure how to do it and have battled for hours. I am sure there is a problem with the mysql insert too.

<?php


    if($ps != "2"){

    ?>

<FORM ENCTYPE="multipart/form-data" ACTION="admin.php?p=addProductItem&ps=2" METHOD="POST">
  <table width="66%" border="0" cellspacing="0" cellpadding="5">
    <tr>
      <td width="26%" align="left" valign="top">First name</td>
      <td width="74%" align="left" valign="top">
          <input name="first" type = "text" size="40" />
        </td>
    </tr>
    <tr>
      <td align="left" valign="top">Last name:</td>
      <td align="left" valign="top"><input name="last" type = "text" size="40" id="last" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">Age:</td>
      <td align="left" valign="top"><input name="age" type = "text" size="40" id="age" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">Email:</td>
      <td align="left" valign="top"><input name="email" type = "text" size="40" id="email" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">Phone:</td>
      <td align="left" valign="top"><input name="phone" type = "text" size="40" id="phone" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">A bit about you:</td>
      <td align="left" valign="top"><textarea name="content" cols="60" rows="10"></textarea></td>
    </tr>
    <tr>
      <td align="left" valign="top">Image:</td>
      <td align="left" valign="top">
          <input name="userfile" type="file" />
        </td>
    </tr>
    <tr>
      <td align="left" valign="top">Image:</td>
      <td align="left" valign="top"><input name="userfile2" type="file" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">
          <input type="submit" value="submit" />
        </td>
      <td align="left" valign="top"></td>
    </tr>
    <tr>
      <td align="left" valign="top"> </td>
      <td align="left" valign="top"> </td>
    </tr>
  </table>
  <br>
</FORM>
<?php

    }

    else{

      $add="uploaded/".$_FILES[userfile][name];

      $add2 = "../".$add;

      if(move_uploaded_file ($_FILES[userfile][tmp_name], $add2)){

        $Q = mysql_query("INSERT INTO productitem (`first`,`last`,`age`,`email`,`phone`,`content`,`phone`,`content`,`file`,`file2`) VALUES ('$first','$last','$age','$email','$phone','$content','$add','$add')");

        echo "Added Successfully";

      }

      else{

        echo "Add Failed";

      }

    }

?>

[emediastudios]

I changed it to this, but is still wrong, im hopeless.

 

<FORM ENCTYPE="multipart/form-data" ACTION="model_application.php" METHOD="POST">
  <table width="66%" border="0" cellspacing="0" cellpadding="5">
    <tr>
      <td width="26%" align="left" valign="top">First name</td>
      <td width="74%" align="left" valign="top">
          <input name="first" type = "text" size="40" />
        </td>
    </tr>
    <tr>
      <td align="left" valign="top">Last name:</td>
      <td align="left" valign="top"><input name="last" type = "text" size="40" id="last" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">Age:</td>
      <td align="left" valign="top"><input name="age" type = "text" size="40" id="age" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">Email:</td>
      <td align="left" valign="top"><input name="email" type = "text" size="40" id="email" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">Phone:</td>
      <td align="left" valign="top"><input name="phone" type = "text" size="40" id="phone" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">A bit about you:</td>
      <td align="left" valign="top"><textarea name="content" cols="60" rows="10"></textarea></td>
    </tr>
    <tr>
      <td align="left" valign="top">Image:</td>
      <td align="left" valign="top">
          <input name="userfile" type="file" />
        </td>
    </tr>
    <tr>
      <td align="left" valign="top">Image:</td>
      <td align="left" valign="top"><input name="userfile2" type="file" /></td>
    </tr>
    <tr>
      <td align="left" valign="top">
          <input type="submit" value="submit" />
        </td>
      <td align="left" valign="top"></td>
    </tr>
    <tr>
      <td align="left" valign="top"> </td>
      <td align="left" valign="top"> </td>
    </tr>
  </table>
  <br>
</FORM>
<?php

if(isset($_POST['submit'])){

      $add="uploaded/".$_FILES[userfile][name];
  $add2="uploaded/".$_FILES[userfile2][name];

      if(move_uploaded_file ($_FILES[userfile][tmp_name])){

        $Q = mysql_query("INSERT INTO applicants (`first`,`last`,`age`,`email`,`phone`,`content`,`phone`,`content`,`file`,`file2`) VALUES ('$first','$last','$age','$email','$phone','$content','$add','$add2')");

        echo "Added Successfully";

      }

      else{

        echo "Add Failed";

      }

    }

?>