benzeina Posted September 19, 2006 Share Posted September 19, 2006 Hi everyone,I've been trying this for two days. I feel hopeless Sad. Basically I managed to load an image to my mysql. the problem is when displaying the image. It returns about 400 lines of this ---> "x���yr��{�ΐN����E<�l>A�fLF������".here is my image insertion:if ($_POST['Submit']) {if ($_POST['MAX_FILE_SIZE'] >= $_FILES['file']['size']) {//print_r($_FILES);mysql_connect("localhost", "username", "password") or die(mysql_error());mysql_select_db("Vehicles");$photo = addslashes(fread(fopen($_FILES['file']['tmp_name'], "r"), $_FILES['file']['size']));$query = sprintf("INSERT INTO Cars(Picture, FileType) VALUES ('%s', '%s')", $photo, $_FILES['file']['type']);Is there something missing. I do have the 'Picture' field of type BLOB !and i use this to retrieve it:<img src="<?php echo $result_ar['Picture']; ?>" width="144" height="108" border="0" id="Image1" />[/url][/url]</td>I would really appreciate your help. Thank you so much in advance.Ben Quote Link to comment Share on other sites More sharing options...
fenway Posted September 20, 2006 Share Posted September 20, 2006 Well, what you've stored in the DB is the actual binary content of your file -- you'll need to return this information, with appropriate headers, if you want to serve it on-the-fly. This will necessitate another script that streams this data appropriately, which you will then call with via src attribute on your IMG tag (and simply pass it a UID or other unique value to lookup). I've seen many examples of such a code snippet posted in this forum recently as well. Quote Link to comment Share on other sites More sharing options...
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