Help me fix this querry - going nuts!

[tom11011]

Basically, there are 2 required fields, but if other fields have data in them, it should query them.  Thenks in advance.

[code]
$query = "SELECT * FROM table WHERE sl = '$sl' and state = '$state'";

                if (strlen($type) > 0) {
                        $query = $query + " and type = '$type'";
                        }
                if (strlen($city) > 0) {
                        $query = $query + " and city = '$city'";
                        }
                if (strlen($zip) > 0) {
                        $query = $query + " and zip = '$zip'";
                        }
                if (strlen($status) > 0) {
                        $query = $query + " and status = '$status'";
                        }
                if (strlen($pricemin) > 0) {
                        $query = $query + " and price >= '$pricemin'";
                        }
                if (strlen($pricemax) > 0) {
                        $query = $query + " and price <= '$pricemax'";
                        }
                if (strlen($squarefeetmin) > 0) {
                        $query = $query + " and squarefeet >= '$squarefeetmin'";
                        }
                if (strlen($squarefeetmax) > 0) {
                        $query = $query + " and squarefeet <= '$squarefeetmax'";
                        }
                if (strlen($ppsfmin) > 0) {
                        $query = $query + " and ppsfmin >= '$ppsfmin'";
                        }
                if (strlen($ppsfmax) > 0) {
                        $query = $query + " and ppsfmax <= '$ppsfmax'";
                        }
                $query = $query + " ORDER BY price;";
[/code]

[obsidian]

close:
[code]
<?php
$query = "SELECT * FROM table WHERE sl = '$sl' and state = '$state'";
if (!empty($type)) $query .= " AND type = '$type'";
if (!empty($city)) $query .= " AND city = '$city'";
if (!empty($zip)) $query .= " AND zip = '$zip'";
// and so on
?>
[/code]

[tom11011]

thanks!  worked.