basic image question

[Vitamin]

OK, I think this is easy, but I just can't seam to get it figured out.

 

I have this piece of code

 

echo '<img src="maps/' . $map . '.jpg" />';

 

And what I want to do is if that $map is not in the directory I want it to display a standard image that I know is in the directory.

 

So basically I want the alt tag to be a image instead of text.

[mraza]

file_exists

 

$filename = "maps/" . $map . ".jpg";

if (file_exists($filename)) {
   echo '<img src="maps/' . $map . '.jpg" />';
} else {
   echo '<img src="maps/otherimage.jpg" />';
}

 

 

[fortnox007]

I think you can also make an if-statement before you output this line of text that way you can set the  image variable to a path stored in the database and if that field is empty set it to a default image path. Much easier to implement.

 

To give a simple example:

 

<?php
if($result_from_db_field == '') { // so if the field in the database (that stores the path to the img) is empty
$map = '/pathto/default.jpg';
}else{
$map = $result_from_db_field; // so if the path is stored in the database.
}
?>
<!---  your html under here with $map in it -->

[Vitamin]

Thanks really appreciated it.  I don't know why, but I could not figure this one out for the life of me.

 

And also thanks for the fast reply.