dean7 Posted September 30, 2010 Share Posted September 30, 2010 Hi all, ive just coded a new thing for my website which lets users upgrade there car to a certain speed, its all coded and works fine, but im just not sure how todo one thing on it. <?php $getall = mysql_query("SELECT car, id FROM garage WHERE owner='$username'"); while($row = mysql_fetch_array($getall)){ echo $row['car']. " - ". $row['id']; echo "<br />"; } ?> That bit of my code, select the car and the car ID from my table garage, but i'm wanting it in a drop down box which shows all the cars in there garage, but not sure how I would do this. Any advice? Thanks. Link to comment https://forums.phpfreaks.com/topic/214838-drop-down-box/ Share on other sites More sharing options...
petroz Posted September 30, 2010 Share Posted September 30, 2010 This should create a dropdown menu... <?php $getall = mysql_query("SELECT car, id FROM garage WHERE owner='$username'"); echo "<select>"; while($row = mysql_fetch_array($getall)){ echo '<option value="'.$row['id'].'">'; echo $row['car'].'</option>'; //echo $row['car']. " - ". $row['id']; //echo "<br />"; } echo "</select>"; Link to comment https://forums.phpfreaks.com/topic/214838-drop-down-box/#findComment-1117643 Share on other sites More sharing options...
Pikachu2000 Posted September 30, 2010 Share Posted September 30, 2010 One thing, remember to add a name= attribute to the <select> tag . . . Link to comment https://forums.phpfreaks.com/topic/214838-drop-down-box/#findComment-1117644 Share on other sites More sharing options...
petroz Posted September 30, 2010 Share Posted September 30, 2010 Oops! Good catch! Link to comment https://forums.phpfreaks.com/topic/214838-drop-down-box/#findComment-1117646 Share on other sites More sharing options...
dean7 Posted September 30, 2010 Author Share Posted September 30, 2010 Ah thanks that worked . Link to comment https://forums.phpfreaks.com/topic/214838-drop-down-box/#findComment-1117650 Share on other sites More sharing options...
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