next birthday date

[brown2005]

if

$birthdate = "2006-03-30";

how can i write a function that will tell me when the next birthday is.

i.e. 30-03-2007....

[Orio]

[code]<?php

$nums=explode("-",$birthdate);
$nums[0]++;
echo implode("-",$nums);

?>[/code]

Orio.

[brown2005]

... i dont understand the code above, it just comes out with one. that isnt wat i want....

[obsidian]

[quote author=brown2005 link=topic=108907.msg438644#msg438644 date=1158839368]
if

$birthdate = "2006-03-30";

how can i write a function that will tell me when the next birthday is.

i.e. 30-03-2007....
[/quote]
well, since birthdays are always the same month and day every year, just try something like this:
[code]
<?php
// define birthday
$birthdate = "2006-03-30";

// split date up into pieces
list($year, $month, $day) = explode('-', $birthdate);

// create next birthday
$next = date('Y-m-d', mktime(0,0,0,$month,$day,$year + 1));
echo $next;
?>
[/code]

hope this helps

[redarrow]

sorry but i dont understand your logic can you kindly tell me why you want to show next users birthdays i thort all you have to do is show todays birthdays.

[brown2005]

i just want to know the date of someones next birthday, no logic, no todays birthdays, just that.

[brown2005]

what do u mean u thought all i have to do is show todays birthdays? why?

[Wintergreen]

Does it matter why he wants to show it? 

[brown2005]

that is my thoughts exactly, but didnt want to sound as if i was being rude.. lol

[Wintergreen]

Obsidian's method looks good

[brown2005]

hi obsidian,

if say i use 30-03-1983 it prints out 30-03-1984, cause it just adds 1 onto the date provided.

so what i think i need to do is work out the age of the person and use this and if it has gone this year add 1 to it or not leave as is....

ne ideas?

[xyn]

If you go on www.php.net search mktime(); in functions
you will be told exactly how to set the same day, and month 1 year on..

Which as obsidian clearly stated above that method should work...

[brown2005]

yes but it is not 1 year on is it...

we are in 2006... my next birthday based on 30-03-1983 is

30-03-2007 not 30-03-1984.

[redarrow]

sorry if you all got so mad with me asking a quistion, but as a php programmer and a designer it's always nice to keep up with the times.

[obsidian]

you've got to use YYYY-MM-DD format like you showed in your first post. as for your last question about the age, i don't understand what you're asking.

[brown2005]

i aint mad! i never get mad! theres no point! i just dont have any specific reason for wanting it.

[obsidian]

[quote author=redarrow link=topic=108907.msg438681#msg438681 date=1158843426]
sorry but i dont understand your logic can you kindly tell me why you want to show next users birthdays i thort all you have to do is show todays birthdays.
[/quote]

there are several reasons i can think of to show someone's [b]next[/b] birthday. the most logical of which is a profile. if you're showing their birthday and it's already past this year, you want to show their [i]upcoming[/i] birthday. as for, "keeping up with the times", as you put it, i fail to see what relevance that has on understanding WHY he's wanting to do what he's doing ???

[brown2005]

rite

the script u have written obisidan adds 1 to the year so my birthday

1983-03-30

with your script is

1984-03-30

wat i want is not 1 year after my birthday, i want the next birthday as u have stated, but from the birthdate, not the date of this year 2006-03-30 as i think you think i mean...

[obsidian]

no problem... try this out:
[code]
<?php
function getNextBDay($bday) {
  list($bd_year, $bd_month, $bd_day) = explode('-', $bday);
  $today = date('Y-m-d');
  list($td_year, $td_month, $td_day) = explode('-', $today);
 
  // get your birthday of this year in timestamp
  $thisBday = mktime(0,0,0,$bd_month, $bd_day, $td_year);
  if ($thisBday < mktime(0,0,0,$td_month, $td_day, $td_year)) {
    // birthday has passed, so increment the year
    $thisBday = mktime(0,0,0,$bd_month, $bd_day, $td_year + 1);
  }

  return date('Y-m-d', $thisBday);
}

$birthday = "1983-03-30";
echo getNextBDay($birthday);
?>
[/code]

hope this helps

[brown2005]

thank you very much, exactly what i need