date time function

[fantomel]

hello i got this small function i`m working on to get the date of a month something like get current date - 1 but not sure how to handle jan month can someone help me please ?

 

 

 

$month = date('m') - 1;$date_startt = date('Y').'-'.$luna.'-01';$timestamp_start = strtotime($data_start);

 

[BlueSkyIS]

can you explain what your final result should be? also, where is $luna defined?

[fantomel]

can you explain what your final result should be? also, where is $luna defined?

 

 

umm sorry my bad

 

 

$month = date('m') - 1;$date_startt = date('Y').'-'.$month.'-01';$timestamp_start = strtotime($date_startt);

 

 

well the final result should be like this:

today : Sat 31 Oct 2010

and i want to find out the date of a month ago and if it's January you know that Jan sometimes got +1 day or -1 one day and i need to calculate this correct.

[BlueSkyIS]

The number of days in January never changes. Do you mean February? Here is how I would get the time of one month ago:

 

 

$now_parts = get_date();$time_one_month_ago = mktime($now_parts['hours'], $now_parts['minutes'], $now_parts['seconds'], $now_parts['mon'] - 1, $now_parts['mday'], $now_parts['year']);

 

 

but if you want 30 days instead of 1 month it would be this:

 

 

$now_parts = get_date();$time_one_month_ago = mktime($now_parts['hours'], $now_parts['minutes'], $now_parts['seconds'], $now_parts['mon'], $now_parts['mday'] - 30, $now_parts['year']);

 

[jcbones]

$date = new DateTime();
$date->sub(new DateInterval('P1M'));
echo $date->format('m-d-Y');

[BlueSkyIS]

^ Gosh, that is so much more concise. Thanks for that. I must remember the DateTime object...

[fantomel]

thank you very much for you responses.