get filenames from directory and display each in a cell no wider than 5 columns

[joshd963]

Hi guys. Just a quick PHP question. I have a script running that gets the files from a directory. There is then a switch function that decides what to do with the file, ie... if it is a PNG... DO THIS.. if it is a docx... DO THIS.. etc.

And i want each file to be in a different cell on the table. The table can be longer wider than 5 columns (however it can be as high as it wants). I currently have this bit working... but instead of one item in each cell... it is displaying every item in each cell. Any ideas Chaps? Here is my code 

Many thanks in advance if you could possibly help..

echo "<table><tr>";
$count = count(glob("../../shared/files/*.*", GLOB_BRACE));
for($i=1; $i <= $count; $i++) 
{ 
///
echo "<td>";
///
if ($handle = opendir('../../shared/files/')) {
    while (false !== ($file = readdir($handle))) {
        if ($file != "." && $file != "..") {

$break = pathinfo($file);
$b = $break['extension'];

switch (@$break[extension]) { 
case 'bmp' : 
    echo 'A BMP<br>'; 
    break;

case 'png' :
    echo 'A PNG<br>';
    break;

case  'doc' :
case 'docx' :
    echo 'A DOC OR DOCX<br>';
    break;
             
default:
     echo 'FILE NOT RECOGNISED<br>';

}
}
}
    closedir($handle);
}

///

echo "</td>";
///

if($i % 3 == 0) 
    echo "</tr><tr>"; 
} 
echo "</tr></table>";
?>

 

[Zane]

This,

if($i % 3 == 0) 
    echo ""; 
} 

Should be at the BEGINNING of your loop, not the end.

[joshd963]

hmm.. im not entirely sure what you mean 

 

Regards

Josh

[Zane]

This,

if($i % 3 == 0) 
    echo ""; 
} 

Should be at the BEGINNING of your loop, not the end.

 

I mean this

echo "</pre>
<table>";
$count = count(glob("../../shared/files/*.*", GLOB_BRACE));
for($i=1; $i { 
/// Put it here if($i % 3 == 0) 
    echo ""; 
} 
///// echo "";
</

 

[joshd963]

"top nutter"

 

Thanks a lot for your help :-)

 

it now works, & i understand. Cheers