Function parameter

[assgar]

 

Hello

 

I am experiencing some issues with a function and I cannot identify the problem.

The function is not receiving any parameter.

 

The URL values are passed correctly.  I used echo to display the parameters outside the function and that worked.

I also used echo to display the parameters inside the function and no parameter were displayed. 

So the function is not receiving parameters. 

 

 

<?php

$find = $_REQUEST['u_find'];
$field = $_REQUEST['u_field'];
$searching = $_REQUEST['u_search'];


echo"(1a)$find, (1b)$field, (1c)$searching";//outside function

function test_display($searching, $field, $find)
{
   echo"(2a)$find, (2b)$field, (2c)$searching";//inside function

}

?>

[BlueSkyIS]

you never call the function test_display(), so it will never run. add this after the function definition, an example of calling the function:

 

test_display('hello', 'world', '1234abcd');

[assgar]

Hello

 

The problem still exists as described.

 

I was trying to keep it simple, below is the function call being used.

NOTE: The function is a separate script that is linked to the page using

 

<?
include("../display");  //link separate script

   test_display($searching, $field, $find);//call function
?>

[jcbones]

So give us the correct script, as guessing will get us no where.  Therefore, we will continue to get feedback of "its still not working".

 

 

 

[PFMaBiSmAd]

It's probably because you are using short open tags <? and you php code is not being seen as php code.

 

Use full opening tags <?php