doddsey_65 Posted October 29, 2010 Share Posted October 29, 2010 I have this javascript code which uses mouseover for a tooltip. It works fine until i add php. Anyone know how i could add the php variable? Here is the original code: <span class="users_browsing" onmouseover="tooltip.show('hi');" onmouseout="tooltip.hide();"> Ive tried this but it doesnt work: echo "<span class=\"users_browsing\" onmouseover=\"tooltip.show(\"{$content1}\");\" onmouseout=\"tooltip.hide();\"> Users Browsing Forum: {$browsers_num}</span>"; Quote Link to comment https://forums.phpfreaks.com/topic/217171-php-variable-in-javascript/ Share on other sites More sharing options...
doddsey_65 Posted October 29, 2010 Author Share Posted October 29, 2010 no one know the answer? or is this too easy that i should figure it out myself? ive tried several different methods but cant get it to work. Quote Link to comment https://forums.phpfreaks.com/topic/217171-php-variable-in-javascript/#findComment-1127858 Share on other sites More sharing options...
Anti-Moronic Posted October 29, 2010 Share Posted October 29, 2010 First, get firebug (or equiv) and find out if your js is returning any errors when you run the function. It is because you are not using ' for your js. tooltip.show('hi'); tooltip.show("$content1"); try: echo "<span class=\"users_browsing\" onmouseover=\"alert('{$content1}');\" onmouseout=\"\"> Users Browsing Forum: {$browsers_num}</span>"; Quote Link to comment https://forums.phpfreaks.com/topic/217171-php-variable-in-javascript/#findComment-1127863 Share on other sites More sharing options...
doddsey_65 Posted October 29, 2010 Author Share Posted October 29, 2010 i got firebug but dont know how to use it, so i dont know about any errors. I have tried your code and the same thing happens. It just echoes the html after the mouseover. You can see it here: http://www.thevault.cz.cc/index.php?forum=1&topic=52 Quote Link to comment https://forums.phpfreaks.com/topic/217171-php-variable-in-javascript/#findComment-1127865 Share on other sites More sharing options...
PFMaBiSmAd Posted October 29, 2010 Share Posted October 29, 2010 The $content1 that you are putting into the alert() box is breaking the Javascript syntax. If you are trying to style the alert box/contents, you need to do something like - http://javascript.internet.com/miscellaneous/custom-alert-box.html Quote Link to comment https://forums.phpfreaks.com/topic/217171-php-variable-in-javascript/#findComment-1127874 Share on other sites More sharing options...
doddsey_65 Posted October 29, 2010 Author Share Posted October 29, 2010 i fixed it. $content1 didnt just contain the usernames it also contained a <span> which had a class grabbed from a switch. I just reordered a few things and added the span to the javascript before content1 was called. Quote Link to comment https://forums.phpfreaks.com/topic/217171-php-variable-in-javascript/#findComment-1127876 Share on other sites More sharing options...
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