PHP session?

[Hrvoje]

Pls tell me what is wrong?

 

<?PHP
include("dba.php");

function hvataj ($trazi, $id)
{
$upit = mysql_query ('select * from administrator where member_id = '.$id.'');

return ( $row = mysql_fetch_assoc ($upit)  ) ? $row[$trazi] : mysql_error ();
}
?> 

 

I have parse error here on this line when I want to echo it:

 

<?PHP echo "<img src='images/korisnik_slike/".hvataj('slika',$_SESSION['member_id']."' />"; ?>

[jdavidbakr]

You're missing a closing ")" in your call to hvataj()

[Hrvoje]

aaarrg )))

 

Thanks

[Hrvoje]

Many thanks for this ) close.

 

But I have another question.

 

Now I have that simple script, when admin loged in than echo avatar of that admin.

 

Nothing happens??

 

<?php

include("dba.php");

function hvataj ($trazi, $id){

if(!$_SESSION['member_id']){

$upit = mysql_query ('select * from administrator where member_id = '.$id.'');

return ( $row = mysql_fetch_assoc ($upit)  ) ? $row[$trazi] : mysql_error ();
} 

?>



<?php

echo "<img src='images/slika_korisnik/".hvataj('slika',$_SESSION['member_id'])."' width='82' height='82' />"; 

?>


<?PHP
}
?>

[jdavidbakr]

Are you sure you're getting a row in your query?  Try echoing the query right after you compose it and double-check it by copying it into phpMyAdmin.