Sleeper Posted November 27, 2010 Share Posted November 27, 2010 Hello. I am working on something where I don't want to do this.... if ($pages <= 1){$P=1;} elseif ($pages > 1 && $pages <= 2){$P=2;} elseif ($pages > 2 && $pages <= 3){$P=3;} elseif ($pages > 3 && $pages <= 4){$P=4;} elseif ($pages > 4 && $pages <= 5){$P=5;} elseif ($pages > 5 && $pages <= 6){$P=6;} elseif ($pages > 6 && $pages <= 7){$P=7;} elseif ($pages > 7 && $pages <= {$P=8;} elseif ($pages > 8 && $pages <= 9){$P=9;} elseif ($pages > 9 && $pages <= 10){$P=10;} This could go on and on and I would rather use the for $ i++ for this so it will wright out the coding for as little or as much as it needs rather then I. However I am not sure how I would do this. I also have if ($PN == 1){$L = "0,20";} elseif ($PN == 2){$L = "20,20";} elseif ($PN == 3){$L = "40,20";} elseif ($PN == 4){$L = "60,20";} elseif ($PN == 5){$L = "80,20";} elseif ($PN == 6){$L = "100,20";} were I will need to be able to add 20 to the number. Is this easily done? I'm a bit loss tried a few things and its not working properly. Quote Link to comment Share on other sites More sharing options...
Sleeper Posted November 27, 2010 Author Share Posted November 27, 2010 ok I was able to do.. $i=1; while ($i <= ($pages+1)) { $G= $i+1; if ($pages <= 1){$P=1;} elseif ($pages > $i && $pages <= $G){$P=$G;} $i++; } to solve the first issue. However the second one were I have to add one to each of the PN's but then add 20 to the Limit not sure how I would do that now. Quote Link to comment Share on other sites More sharing options...
Sleeper Posted November 27, 2010 Author Share Posted November 27, 2010 for ($i=1; $i <= ($pages+1); $i++) { $G= $i+1; if ($pages <= 1){$P=1;} elseif ($pages > $i && $pages <= $G){$P=$G;} } This works as well. But I still don't know how to add 20 each time to a number rather then just 1. Quote Link to comment Share on other sites More sharing options...
Pikachu2000 Posted November 27, 2010 Share Posted November 27, 2010 Unless I'm completely misunderstanding your intentions, the first block of code is the same as this: if( $pages <= 1 ) { $P = 1; } else { $P = $pages; } I see no reason why the second block couldn't be written as: if( !isset($PN) || $PN < 1) { $PN = 1; } $L = (($PN * 20) -20) . ", 20"; Quote Link to comment Share on other sites More sharing options...
Sleeper Posted November 27, 2010 Author Share Posted November 27, 2010 $L = (($PN * 20) -20) . ", 20"; duh. Sometimes the simplest idea is the best, not sure why I didn't think of that before. The first one is pulling out the number of rows in the table, so that I can put page 1,2,3 and so on. So if there are 83 rows at 25 per page you get 3.32 pages. So its assigning the that there will be 4 pages. The script on the page just pulls up 4 so I can say you are on page 1 of "4". but thank you for the second one, much simple way of doing it. I did just sort out that I could use... $j=2; $ln=25; while ($j <= ($PN)) { $G= $j+1; if ($PN == 1){$L = "0,25";} elseif ($PN == $j){$L = "$ln,25";} $i++; $ln+25; } and that dose the trick, however one line verses that is much better..lol. Thanks again. Quote Link to comment Share on other sites More sharing options...
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