Question on preg_match function

[cc4digital]

Hello Everyone;

 

What I want to do is validate the user has only put a whole number.  eg. 1  , 10 ,  or 100

 

What I do not want is them to put 10.1.

 

So what I have is--

$pricecheckpattern ="#^[0-9]{0}#";
if (preg_match($pricecheckpattern, $years))
{
	echo "This has passed validation for year {$years} <br />";
}
else
{
	echo "This has passed validation for year {$years}<br />";
}

 

The problem is it will accept 10.1, which I do not want. :'(

 

Any help on this would be GREAT.

[ManiacDan]

The number in the curly braces is the number of times you want the item to match.  You're looking for ZERO matches.  Everything has zero occurrences of a digit.

 

That being said, don't use preg_match for this at all:

 

if ( intval($years) == $years ) {
  //whole number
}

-Dan

[Pikachu2000]

You don't need to use a pattern for that. You can use ctype_digit to check that string type data contains only numbers, or is_int to check numeric data types.

[ManiacDan]

ctype_digit is more accurate, Pikachu is right.

[.josh]

If you insist on keeping with the regex route, pattern would be:

 

$pricecheckpattern ="#^[0-9]+$#";

 

(you also forgot to specify end of line anchor)

[cc4digital]

Thanks everyone for your input.  Great.  answered my question a few different ways.

 

Thanks, Crayon Violent for showing me the regex route.  I am finding regex a very difficult concept to master. 

 

Does anyone have any good recommendations on how to learn regex.  I like to use pregmatch(), but I just don't get the patterns. :'(

 

thanks chuck

[.josh]

look at sticky in this forum