President Obama Posted January 24, 2011 Share Posted January 24, 2011 What I want to do is when someone clicks on a link, call a php function in another file which updates the database. This is what I've kinda come up with, doesn't work though. (Uses Jquery) <?php $result3 = array(); $result3[0] = $_POST['result0']; $result3[1] = $_POST['result1']; $result3[2] = $_POST['result2']; $result3[3] = $_POST['result3']; mysql_query("UPDATE adverts SET views = views + 1 WHERE id = $result3[0]")or die(mysql_error()); mysql_query("UPDATE adverts SET views = views + 1 WHERE id = $result3[1]")or die(mysql_error()); mysql_query("UPDATE adverts SET views = views + 1 WHERE id = $result3[2]")or die(mysql_error()); mysql_query("UPDATE adverts SET views = views + 1 WHERE id = $result3[3]")or die(mysql_error()); ?> Jquery: $(document).ready(function(){ var result0 = <?php echo $result3[0]; ?> var result1 = <?php echo $result3[1]; ?> var result2 = <?php echo $result3[2]; ?> var result3 = <?php echo $result3[3]; ?> $('.advert').click(function(){ $.post("functions.php", {result0: "result0", result1: "result1", result2: "result2", result3: "result3" }) }) }); HTML: <a class="advert" href="<?php echo $link['url']; ?>" onclick="window.open('<?php echo $cds[$result3[0]]; ?>')">Banner #1</a> Quote Link to comment https://forums.phpfreaks.com/topic/225460-onclick-post-to-php-form/ Share on other sites More sharing options...
trq Posted January 24, 2011 Share Posted January 24, 2011 Sorry, but that code makes little sense. can you please describe exactly what your trying to do? Quote Link to comment https://forums.phpfreaks.com/topic/225460-onclick-post-to-php-form/#findComment-1164290 Share on other sites More sharing options...
President Obama Posted January 24, 2011 Author Share Posted January 24, 2011 Yeah I redesigned the code, this works kinda. Well it did in a test but in practical it won't, do you see the problem in this? ajax.php <?php if(isset($_POST['functionid'])){ switch ($_POST['functionid']){ case 1: ad1(); break; case 2: ad2(); break; case 3: ad3(); break; case 4: ad4(); break; } } function ad1(){ if(isset($_POST['result'])){ $advert = $_POST['result']; mysql_query("UPDATE adverts SET views = views+1 WHERE id = $advert"); } } ?> Javascript.js: $(document).ready(function() { // Get advert numbers var advert1 = <?php echo $cds[$result3[0]]; ?> var advert2 = <?php echo $cds[$result3[1]]; ?> var advert3 = <?php echo $cds[$result3[2]]; ?> var advert4 = <?php echo $cds[$result3[3]]; ?> $("#advert1").click(function(){ alert("Success") $.post("ajax.php?", {result: advert1, functionid: 1}, function(data){alert("Success")}) }); $("#advert2").click(function(){ $.post("ajax.php?", {result: advert2, functionid: 2}) }); $("#advert3").click(function(){ $.post("ajax.php?", {result: advert3, functionid: 3}) }); $("#advert4").click(function(){ $.post("ajax.php?", {result: advert4, functionid: 4}) }); }); HTML: <a id="advert1" href="<?php echo $link['url']; ?>" onclick="window.open('<?php echo $cds[$result3[0]]; ?>')">Banner #1</a> <a id="advert2" href="<?php echo $link['url']; ?>" onclick="window.open('<?php echo $cds[$result3[1]]; ?>')">Banner #2</a> <a id="advert3" href="<?php echo $link['url']; ?>" onclick="window.open('<?php echo $cds[$result3[2]]; ?>')">Banner #3</a> <a id="advert4" href="<?php echo $link['url']; ?>" onclick="window.open('<?php echo $cds[$result3[3]]; ?>')">Banner #4</a> Quote Link to comment https://forums.phpfreaks.com/topic/225460-onclick-post-to-php-form/#findComment-1164323 Share on other sites More sharing options...
trq Posted January 24, 2011 Share Posted January 24, 2011 Did you read my last reply? Quote Link to comment https://forums.phpfreaks.com/topic/225460-onclick-post-to-php-form/#findComment-1164324 Share on other sites More sharing options...
President Obama Posted January 24, 2011 Author Share Posted January 24, 2011 lol Sorry thought I had included that, what its meant to do is, person clicks ad link, ajax posts ad id to php document which then increases the column view by 1. Quote Link to comment https://forums.phpfreaks.com/topic/225460-onclick-post-to-php-form/#findComment-1164327 Share on other sites More sharing options...
trq Posted January 24, 2011 Share Posted January 24, 2011 It seems a long winded approach, where is $cds defined? Quote Link to comment https://forums.phpfreaks.com/topic/225460-onclick-post-to-php-form/#findComment-1164330 Share on other sites More sharing options...
President Obama Posted January 24, 2011 Author Share Posted January 24, 2011 Fine. include 'config.php'; $result = mysql_query("SELECT * FROM adverts") or die(mysql_error()); // Get Ads $result2 = mysql_query("SELECT * FROM lil_urls WHERE id=$text") or die(mysql_error()); // Get User Link $link = mysql_fetch_array($result2); // Array Convert User Link $ads = array(); // array for ad id $bds = array(); // array for ad url $cds = array(); // array for the two aboved combined to set the index as the id // Fill first 2 arrays while($row = mysql_fetch_array($result)){ $ads[] = $row['id']; $bds[] = $row['url']; } // Combine the 2 arrays to set the index as the id $cds = array_combine($ads, $bds); // Start Generating 4 random numbers to choose 4 random adds $result3 = array(); $numberCount = 4; $thisCount = 0; while($thisCount<$numberCount) { $thisNumber = array_rand($cds); if(!in_array($thisNumber, $result3)) { $result3[$thisCount] = $thisNumber; $thisCount++; } } // End generating. ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html> <head> <script type="text/javascript" src="jquery/jquery.js"></script> <script type="text/javascript" src="jquery/javascript.js"></script> </head> <body> <pre> <?php print_r($result3); print_r($cds); ?> </pre> <a id="advert1" href="<?php echo $link['url']; ?>" onclick="window.open('<?php echo $cds[$result3[0]]; ?>')">Banner #1</a> <a id="advert2" href="<?php echo $link['url']; ?>" onclick="window.open('<?php echo $cds[$result3[1]]; ?>')">Banner #2</a> <a id="advert3" href="<?php echo $link['url']; ?>" onclick="window.open('<?php echo $cds[$result3[2]]; ?>')">Banner #3</a> <a id="advert4" href="<?php echo $link['url']; ?>" onclick="window.open('<?php echo $cds[$result3[3]]; ?>')">Banner #4</a> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/225460-onclick-post-to-php-form/#findComment-1164333 Share on other sites More sharing options...
President Obama Posted January 24, 2011 Author Share Posted January 24, 2011 Don't worry I got it working, was a couple of problems. A) I wasn't connecting to my database at all in the ajax.php B) I didn't use semicolons on the 4 javascript variables, which is strange because I thought javascript didn't need semicolens C) Apparently having the code in another document like I did also stuffs it up, probably because of the php I used in it. Quote Link to comment https://forums.phpfreaks.com/topic/225460-onclick-post-to-php-form/#findComment-1164348 Share on other sites More sharing options...
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