stressedsue Posted September 30, 2006 Share Posted September 30, 2006 Hello,I want to display an image dynamically within the printf() function, where the image name resides on a database. How do I embed the image name within the <img src> tag, which is within the printf() function?Example of code that does not work: printf("<tr> <td> <p><img src='../art/'>%s</p> </td> </tr>\n", $myrow["photoname"]");Any help is greatly appreciated!!! Quote Link to comment Share on other sites More sharing options...
Gaoshan Posted September 30, 2006 Share Posted September 30, 2006 It is the last " causing you trouble (the one right before the closing parenthesis). Lose it and you should be ok.Just curious but why use print_r for this? I think a faster solution would be something like:[code]echo '<tr><td><p><img src="../art/' . $myrow[photoname] . '"></p></td></tr>';[/code] Quote Link to comment Share on other sites More sharing options...
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