jennlaz Posted February 3, 2011 Share Posted February 3, 2011 I'm currently attempting to create my FIRST database driven website, and have hit a serious snag. I'm creating a page that syndicates from another site via .csv, which lists inventory for a car dealership. I've generated the first page successfully, where all of the inventory is listed with a brief description (inventory.php), but now I have to figure out a way to make these descriptions link to a page with more info on the vehicle. Since the inventory will be syndicating from another location, I'd like for these pages to be automatically generated. Now, I am NOT a developer by any stretch of the imagination (front end designer ONLY!), so I'll give an example to try and explain this better. Lets say I have 2 cars in my inventory - a 2008 Dodge Caliber (Stock Number 001) and a 2004 Toyota Echo (Stock Number 002). I've created the inventory.php page where it shows a brief description of the car and an image, and would like the image and description to link to a page generated by the database ("2008-dodge-caliber-001.php" and "2004-toyota-echo-002.php"). How do I make the database automatically create these pages, and how do I link to them from the inventory.php page? I know this is a lot to ask, but if someone could provide me with a code snippet and a layman's terms it would be BEYOND appreciated! Thank you to all who reply!! Quote Link to comment Share on other sites More sharing options...
fenway Posted February 13, 2011 Share Posted February 13, 2011 It doesn't have to be a page -- use a URL parameter -- and then you can get a pretty URL later. Quote Link to comment Share on other sites More sharing options...
jennlaz Posted March 1, 2011 Author Share Posted March 1, 2011 Okay, thank you! I got that part figured out!! Now I'm having another issue (I am not by any means a programmer).. What I did with the parameter was had it send to another page (www.URL.com/page.php?stock=NUMBER). Now I'm trying to have that page display only the data relating to that row of information, using the "SELECT * FROM TABLE1 WHERE STOCK=$stock" (I specified elsewhere that $stock = $_GET['stock'].. But now when I use the "where" function it won't display any of my data. I had it working where it would display one row of data when I manually typed in the stock number, but now that's not working anymore. I don't have a great grasp of code, so I'm trying to play it by ear here. Any suggestions? Thanks guys! Quote Link to comment Share on other sites More sharing options...
peterbarone Posted March 1, 2011 Share Posted March 1, 2011 I'm no pro by any means either. So I run into the same issues you do. First place to start echo $stock somewhere on the page make sure it is being set. I have also noticed that with some php vers. Select * from table1 where stock= '$stock'; If you need php for repeating table let me know Hope that helps a little one noob to another. Lol Quote Link to comment Share on other sites More sharing options...
jennlaz Posted March 2, 2011 Author Share Posted March 2, 2011 I actually figured it out and the answer is a little embarrassing. I moved the $stock = $_GET['stock'] to above the select from and it worked. Lol Quote Link to comment Share on other sites More sharing options...
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