genzedu777 Posted February 13, 2011 Share Posted February 13, 2011 Hi, I am not too sure if I have used the right command, I am using print_r($sql), to view my executed results, but apparently I received mysqli_result Object ( ) , any advice? Thanks $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME) or die(mysqli_error($dbc)); //Run query $tutor_id = mysqli_real_escape_string($dbc, $_GET['tutor_id']); $query = "SELECT tpd.district_id, tpd.district_name, tpz.zone_id, tpz.zone_name FROM tutor_preferred_district AS tpd INNER JOIN tutor_preferred_dlocation AS tpdl USING (district_id) INNER JOIN tutor_preferred_zlocation AS tpzl USING (tutor_id) INNER JOIN tutor_preferred_zone AS tpz USING (zone_id) WHERE tpdl.tutor_id = '{$tutor_id}'"; $sql = mysqli_query($dbc, $query) or die(mysqli_error($dbc)); print_r($sql); Link to comment https://forums.phpfreaks.com/topic/227509-how-do-i-test-and-view-the-results-after-executing-a-sql-command/ Share on other sites More sharing options...
trq Posted February 13, 2011 Share Posted February 13, 2011 Assuming that you want a mysql solution (this is after all the mysql help forum), why not simply execute your query within mysql's cli? Link to comment https://forums.phpfreaks.com/topic/227509-how-do-i-test-and-view-the-results-after-executing-a-sql-command/#findComment-1173506 Share on other sites More sharing options...
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