Alex1646 Posted March 5, 2011 Share Posted March 5, 2011 In my website I want to have a rating system of stoires. I also want to avarage out the ratings (there on a scale of 1-10). I am putting all of my ratings in a array but it doesnt seem to be working. EVerytime I call the array I get a undefined error thingy. $query3 = " SELECT * FROM story_commets WHERE story = '$id_get' ORDER BY date_added "; $select3 = mysql_query($query3) or die(mysql_error()); $x=1; while($rows3 = mysql_fetch_assoc($select3)) { $commetdb = $rows3['commet']; $user_com_db = $rows3['user']; $datedb = $rows3['date_added']; $stardb = $rows3['star']; //get profile picture $query4 = " SELECT * FROM story_commet WHERE user = '$user_com_db' "; $select4 = mysqli_query($dbc, $query4); $rows4 = mysqli_fetch_array($select4); $profile_pic = $rows4['profile_pic']; $user_id = $rows4['id']; echo " <div class='com_info'> <img src='$profile_pic' width='600' height='568' /> <br /> <a href='http://scribofabula.com/soc?p=profile&id=$user_id'> $user_com_id </div> <br /> $datedb <br /> </div> Rating: $stardb/10 <br /> $commetdb "; $ratav[$x]=$stardb; $x++; } Link to comment https://forums.phpfreaks.com/topic/229710-ugghhh-array-is-not-getting-defined/ Share on other sites More sharing options...
Pikachu2000 Posted March 5, 2011 Share Posted March 5, 2011 Where is $id_get defined and assigned a value? What exactly does the 'undefined error thingy' say, pray tell? Link to comment https://forums.phpfreaks.com/topic/229710-ugghhh-array-is-not-getting-defined/#findComment-1183335 Share on other sites More sharing options...
Alex1646 Posted March 5, 2011 Author Share Posted March 5, 2011 $id_get is defined at the begining of the page. There is a lot more code to display the story. But the id_get is the id of the story. As the var name tells it is a get variable. First one: Notice: Undefined variable: ratav in C:\wamp\www\Login\inc\page.php on line 115 Second One: Warning: array_sum() expects parameter 1 to be array, null given in C:\wamp\www\Login\inc\page.php on line 116 Third One: Notice: Undefined variable: ratav in C:\wamp\www\Login\inc\page.php on line 117 Here is the rest of the code if needed: <?php $id_get = $_GET['id']; //grab data from db mysqlConnect(); //query***************************************************** $query1 = " SELECT * FROM story_info WHERE story_id = '$id_get' "; $select = mysql_query($query1) or die(mysql_error()); $rows1 = mysql_fetch_assoc($select); //put data into vars $titledb = $rows1['title']; $sumdb = $rows1['sum']; $notesdb = $rows1['notes']; $storydb = $rows1['story']; $otherdb = $rows1['other']; $userdb = $rows1['user']; $catdb = $rows1['cat']; $ratingdb = $rows1['rating']; //take data from user_info table //query***************************************************** $query2 = " SELECT * FROM login_info WHERE user='$userdb' "; $select2 = mysql_query($query2) or die(mysql_error()); $rows2 = mysql_fetch_assoc($select2); //take data from table $id_db = $rows2['id']; $profile_db = $rows2['profile_picture']; ?> <div class='story'> <h2> <?php echo $titledb; ?> </h2> <?php echo $storydb?> </div> <div class='story_info'> <img src="<?php echo $profile_db;?>" width="172" height="166" /> <br /> <a href="http://scribofabula.com/soc?p=profile&pid=<?php echo $profile_db; ?>"> <?php echo $userdb; ?> </a> ><br /> <h3> Summary </h3> <?php echo $sumdb; ?> <h3>Catagory/Genre:</h3> <a href='http://scribofabula.com/soc?p=cat_view&gen=<?php echo $catdb ?>'> <?php echo $catdb; ?> </a> </p> <h3>Rating:</h3> <?php echo $ratingdb; ?> <?php if (isset($notesdb)) { echo "<h3> Author's Notes: </h3>"; echo $notesdb; } ?> <?php echo "<h3> Other Stories</h3>"; echo $otherdb; ?> </div> <br/> <div class='com'> <h2> Reviews: </h2> <?php $query3 = " SELECT * FROM story_commets WHERE story = '$id_get' ORDER BY date_added "; $select3 = mysql_query($query3) or die(mysql_error()); $x=1; while($rows3 = mysql_fetch_assoc($select3)) { $commetdb = $rows3['commet']; $user_com_db = $rows3['user']; $datedb = $rows3['date_added']; $stardb = $rows3['star']; //get profile picture $query4 = " SELECT * FROM story_commet WHERE user = '$user_com_db' "; $select4 = mysqli_query($dbc, $query4); $rows4 = mysqli_fetch_array($select4); $profile_pic = $rows4['profile_pic']; $user_id = $rows4['id']; echo " <div class='com_info'> <img src='$profile_pic' width='600' height='568' /> <br /> <a href='http://scribofabula.com/soc?p=profile&id=$user_id'> $user_com_id </div> <br /> $datedb <br /> </div> Rating: $stardb/10 <br /> $commetdb "; $ratav[$x]=$stardb; $x++; } $a=1; /* while($a>$array_num) { $ratav_final = array (); $a++; $ratav_final[$a] = $ratav[$a]; } */ print_r($ratav); $sum = array_sum($ratav); $count = count($ratav); $av = $sum * $count; echo"<div id='message'> Rating Avarage: $av /10 </div>"; if (isset($_SESSION['user'])) { echo' <p> Did you like this story? Did you hate it? Give it a rating and let the author know!</p> <form action="commet_res" method="post" enctype="multipart/form-data" target="_self"> <label> Your rating is on a scale of 1-10 </label> <select name="rat"> <option> 1 </option> <option> 2 </option> <option> 3 </option> <option> 4 </option> <option> 5 </option> <option> 6 </option> <option> 7 </option> <option> 8 </option> <option> 9 </option> <option> 10 </option> </select> <label> Commets: </label> <textarea name="commet" cols="70" rows="9"></textarea> </form> '; } else { echo "<div id='message'> Sign in to post a review! </div>"; } ?> Link to comment https://forums.phpfreaks.com/topic/229710-ugghhh-array-is-not-getting-defined/#findComment-1183338 Share on other sites More sharing options...
Pikachu2000 Posted March 5, 2011 Share Posted March 5, 2011 Are those the only errors you're getting? It would make sense in context with the code and the problem if there were more errors than that. Link to comment https://forums.phpfreaks.com/topic/229710-ugghhh-array-is-not-getting-defined/#findComment-1183340 Share on other sites More sharing options...
Alex1646 Posted March 5, 2011 Author Share Posted March 5, 2011 Yep. Thats all the errors Im getting. Link to comment https://forums.phpfreaks.com/topic/229710-ugghhh-array-is-not-getting-defined/#findComment-1183342 Share on other sites More sharing options...
Pikachu2000 Posted March 5, 2011 Share Posted March 5, 2011 Let's try this, then. See the comments in the code; there are four changes to try so we can try to figure out what's going on. Two changes at the beginning, and two at the end. // $x=1; COMMENT OUT THIS LINE $ratav = array(); // INITIALIZE AN EMPTY ARRAY while($rows3 = mysql_fetch_assoc($select3)) { $commetdb = $rows3['commet']; $user_com_db = $rows3['user']; $datedb = $rows3['date_added']; $stardb = $rows3['star']; //get profile picture $query4 = " SELECT * FROM story_commet WHERE user = '$user_com_db' "; $select4 = mysqli_query($dbc, $query4); $rows4 = mysqli_fetch_array($select4); $profile_pic = $rows4['profile_pic']; $user_id = $rows4['id']; echo " <div class='com_info'> <img src='$profile_pic' width='600' height='568' /> <br /> <a href='http://scribofabula.com/soc?p=profile&id=$user_id'> $user_com_id </div> <br /> $datedb <br /> </div> Rating: $stardb/10 <br /> $commetdb "; $ratav[]=$stardb; // CHANGED FROM $ratav[$x] // $x++; COMMENT OUT THIS LINE } Link to comment https://forums.phpfreaks.com/topic/229710-ugghhh-array-is-not-getting-defined/#findComment-1183345 Share on other sites More sharing options...
Alex1646 Posted March 5, 2011 Author Share Posted March 5, 2011 THANK YOU SO MUCH! Link to comment https://forums.phpfreaks.com/topic/229710-ugghhh-array-is-not-getting-defined/#findComment-1183353 Share on other sites More sharing options...
Pikachu2000 Posted March 5, 2011 Share Posted March 5, 2011 Did that make it work as you intended it to work? Link to comment https://forums.phpfreaks.com/topic/229710-ugghhh-array-is-not-getting-defined/#findComment-1183359 Share on other sites More sharing options...
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