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Getting last highest value if current date = 0?


RJP1

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Hi guys,

 

I have a simple table like so:

 

id timestamp value

--------------------------------------

30 1299784130 10000.00

31 1300168969 10500.00

 

Using the following SQL query I am able to get the higest value per day in a date range including days that don't exist in the database (for graphing):

 

SELECT Y.day, MAX(COALESCE(Z.value,0)) as value

FROM (SELECT DATE_ADD( '2011-01-01', INTERVAL a.i + b.i *10 + c.i *100

DAY ) AS DAY

FROM integers a

CROSS JOIN integers b

CROSS JOIN integers c

HAVING DAY BETWEEN '2011-03-10' AND '2011-03-20') Y

LEFT OUTER JOIN `table` Z ON Y.day = DATE(FROM_UNIXTIME(Z.timestamp))

GROUP BY Y.DAY

ORDER BY Y.DAY ASC

 

This yields:

 

day               value

--------------------------------

2011-03-10 10000.00

2011-03-11 0.00

2011-03-12 0.00

2011-03-13 0.00

2011-03-14 0.00

2011-03-15 10345.47

2011-03-16 0.00

2011-03-17 0.00

2011-03-18 0.00

2011-03-19 0.00

2011-03-20 0.00

 

Which is lovely. However, can someone advise how I alter the query to ensure the dates between 2011-03-10 and 2011-03-15 have 10000.00 as their value rather than zero? In other words, if the value comes out as zero, can you help me make it check backwards in time to check for the highest previous value? Thanks!

 

RJP1

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Not as such, I want the days that haven't got a value to have the value of the first day previous to the zero day if that makes sense!

 

In this case 2011-03-11, 2011-03-12, 2011-03-13, 2011-03-14  would = 10000 (because 2011-03-10 = 10000) and 2011-03-16, 2011-03-17, 2011-03-18, 2011-03-19 and  2011-03-20  to = 10345.47 (because 2011-03-15 = 10345.47).

 

Doable? RJP1

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