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HELLO, I HAVE A PROBLEM TO INSERT DATA FROM OUTPUT FROM FUNCTION()...

I WANT TO STORE THE OUTPUT IN DATABASE, BUT FAILED TO INSERT...

 

===============================================

BELOW IS MY FUNCTION() CODE, academiaTotal.php

===============================================

<?php

$page = 'fkpacademia.php';

 

//connect db

 

function totalMac_ac1(){

$query1 = "SELECT AVG(MAC) FROM academia1";

$result1 = mysql_query($query1) or die(mysql_error());

 

while($row1 = mysql_fetch_array($result1)){

echo "".number_format($row1['AVG(MAC)'],1);

 

$sql = "INSERT INTO fkpacademia (MAC) VALUES ('$row1['AVG(MAC)']')";

}

}

 

---?>

 

======================================

MY CALL FUNCTION fkpacademia.php

======================================

<?php require 'academiaTotal.php' ?>

 

<? totalMac_ac1(); ?>

 

 

 

**********************************************

MY PROBLEM NOW IS THE sql(INSERT, (AVG(MAC) output... )) NOT SUCCESS... NO DATA INSERTED IN fkpacademia table.. AND I WANT TO UPDATE ALWAYS (AVG(MAC) from academiaTotal )... (MEANS THAT fkpacademia only have 1 record of AVG(MAC)...)

 

hope anyone can help me...

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i have ask my friend about that.. should i need to insert and update also.. update must do in sql right? but, the problem now is i think the insert above not send any output. cause my table still empty.. i need to store the output from function(), store into db.. so that i do insert but not working... or me myself do wrong for above code..? can u explain to me clearly?

phpMyAdmin - 2.11.7

Server version: 5.0.51b-community-nt

 

 

before this....

.........................

function totalMac_ac1(){

$query1 = "SELECT AVG(MAC) FROM academia1";

$result1 = mysql_query($query1) or die(mysql_error());

 

while($row1 = mysql_fetch_array($result1)){

echo "".number_format($row1['AVG(MAC)'],1);

 

$sql = "INSERT INTO fkpacademia (MAC) VALUES ('$row1['AVG(MAC)']')";

$result=mysql_query($sql);

}

}

..........................

 

 

just now i have this,

bigTotal.php

==============

function bigMac_ac1(){

$sql = "INSERT INTO fkpacademia (MAC) VALUES ('$row1['AVG(MAC)']')";

$result=mysql_query($sql);

 

$query1a = "SELECT AVG(MAC) FROM fkpacademia";

$result1a = mysql_query($query1a) or die(mysql_error());

 

while($row1 = mysql_fetch_array($result1a)){

echo "".number_format($row1['AVG(MAC)'],1);

 

}

}

 

 

========================

fkpacademia.php

========================

<?php require 'bigTotal.php' ?>

<? bigMac_ac1(); ?>

 

 

 

problem: no data store in table fkpacademia..

please somenone help me where the wrong...

I put your original code into my editor and it showed an error on your insert line. Try changing things to this and let me know..

 

echo "".number_format($row1['AVG(fcmb)'],1);
$NUM = number_format($row1['AVG(fcmb)'],1);
$sql = "INSERT INTO fkpacademia (MAC) VALUES ($NUM)";
$result=mysql_query($sql);

 

 

thanks sunfighter...

i have try ur idea, it give what i want (to store in fkpacademia table), but a little problem, it goes to double row from the academia... (speak broken english..sorry), and so that i just change back to be like this,

 

echo "".number_format($row1['AVG(MAC)'],1);

$NUM = number_format($row1['AVG(MAC)'],1);

$sql = "INSERT INTO fkpacademia (MAC) VALUES ($NUM)";

$result=mysql_query($sql);

 

just change the name variable, it give only one row inserted.. and every changes of AVG, it go to next row in the table... (means i should do UPDATE here)... but its okay.. my problem solved right now.. THANKS A LOT...  :D

-------------------------------------------

 

$sqll = "UPDATE fkpacademia SET MAC = '$NUM' WHERE BIL='$BIL' ";

    $result=mysql_query($sqll);

 

 

anyone, data above will be updated, after next to next row..

i want it updated from their row only...

like i want to set,  $NUM1 = $BIL1, $NUM2 = $BIL2, something like that...

how can i do that..?

 

i'm beginner in programming...

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