The_Dude_1978 Posted April 3, 2011 Share Posted April 3, 2011 Hi Guy's, I've recoded allot with 3 scripts i had to my disposal. I've fixed 95% and i'm proud allready, but stuck at the following code. It does'nt execute any errors and refreshes the page without uploading the picture to the desired folder. Also folders are'nt created. I've turned on error reporting at level -1, but those errors i fixed. Can you please help me out? note: this is a partial code of a tiny usermanagement 'cms'. <?php //action: add picture for user ----------------------------------------------------------------------------- if (isset($_GET['editpic']) && isset($_GET['id'])) { $id = (int) $_GET['id']; if ($id == 0) { die("Invalid ID provided."); } $sql = "SELECT username FROM `users` WHERE `id`='".$_GET['id']."'"; $res = mysql_query($sql) or die(mysql_error()); //execution when completed the add picture form and pressed submit button --------------------- if (isset($_POST['addPic'])) { $row = mysql_fetch_assoc($res); $title = protect($_POST['title']); if(!$title) { echo "<script language=\"Javascript\" type=\"text/javascript\"> alert(\"You must choose a title for your picture!\") document.location.href='profilecp.php'</script>"; } $target = $row['username']; if(!is_dir($target)) @mkdir($target); $target = $target . '/pics'; if(!is_dir($target)) @mkdir($target); $target = $target."/".basename($_FILES['pics']['name']) ; $size = $_FILES['pics']['size']; $pic = $_FILES['pics']['name']; $type = $_FILES['pics']['type']; $sql2= "INSERT INTO `user_photos` (`profile_id`,`title`,`size`,`type`,`reference`) VALUES ('".$_GET['id']."','$title','$size','$type','$pic'); "; $res2 = mysql_query($sql2) or die(mysql_error()); if(move_uploaded_file($_FILES['pics']['tmp_name'], $target)) { echo "<script language=\"Javascript\" type=\"text/javascript\"> alert(\"Your picture has been uploaded\") document.location.href='profilecp.php'</script>"; } else { echo "<script language=\"Javascript\" type=\"text/javascript\"> alert(\"There was an error, try again\") document.location.href='profilecp.php'</script>"; } $target2 = $row['username']; $target2 = $target2 . '/pics'; $target2 = $target2 . '/thumbs'; if(!is_dir($target2)) @mkdir($target2); $target2 = $target2."/".basename($_FILES['pics']['name']) ; createthumb($target,$target2,150,150); } <!-----------------------ADD PICTURES-----------------------//--> <div class="dividerp"> <form enctype="multipart/form-data" method="POST" action="administrator.php?editpic&id=<?php echo $id;?>"><br/> <strong>Upload Pictures</strong><br/><br/> <div class="formElm"> <label for="title">Title</label> <input id="title" type="text" name="title" maxlength="32"><br/> </div> <div class="formElm"> <label for="file">File</label> <input id="file" type="file" name="pics" maxlength="255"><br/> </div> <input type="submit" name="picAdd" value="Add"> </form> </div> </div> </body> </html> }?> and the mysql tables: CREATE TABLE `users` ( `id` INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY , `first` VARCHAR( 32 ) NOT NULL , `last` VARCHAR( 32 ) NOT NULL , `username` VARCHAR(32) NOT NULL, `password` VARCHAR(255) NOT NULL, `email` VARCHAR(255) NOT NULL, `about` TEXT NOT NULL, `level` int(4) default '1' ) ENGINE=InnoDB AUTO_INCREMENT=27 DEFAULT CHARSET=latin1; CREATE TABLE `user_photos` ( `id` INT NOT NULL AUTO_INCREMENT PRIMARY KEY , `profile_id` INT NOT NULL , `title` VARCHAR( 128 ) NOT NULL , `size` INT NOT NULL , `type` VARCHAR( 128 ) NOT NULL , `reference` VARCHAR( 255 ) NOT NULL ) ENGINE=InnoDB AUTO_INCREMENT=27 DEFAULT CHARSET=latin1; Best regards, Martijn Quote Link to comment Share on other sites More sharing options...
The_Dude_1978 Posted April 4, 2011 Author Share Posted April 4, 2011 Okay, i was'nt paying attention, because it was late in the evening, The variable in the form was name="picAdd" en should have been addPic. Topic solved. Best regards, Martijn Quote Link to comment Share on other sites More sharing options...
spiderwell Posted April 4, 2011 Share Posted April 4, 2011 Okay, i was'nt paying attention, because it was late in the evening, The variable in the form was name="picAdd" en should have been addPic. Topic solved. Best regards, Martijn If I had a dollar for everytime I spent hours looking for a silly mistake like this, I'd be very rich by now Quote Link to comment Share on other sites More sharing options...
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