counting certain words in a string

[dadamssg87]

I can't seem to find a decent code function to search for "curse" words that i would deem inappropriate in an array. Count the number of instances the function finds a curse word and then if the number is greater than one halt the script.

 

something like the following but not really....

$words = array('ass','fuck','shit');
$string = 'Blah blah blah ass blah blah fuck blah blah shit!';
//code to count the instances of the curse words(3)
if($instances > 0)
{
echo "no cursing please.";
} ;

 

any help on how to do this would be much appreciated!

[3raser]

EDIT Sorry, fixed it.

 

<?php

$words = array('ass','fuck','shit');

$string = 'Blah blah blah ass blah blah fuck blah blah shit!';
$validate = explode(" ", $string);

if(in_array($words))
{
echo "No cursing please.";
}
else
{
//no cussing found
}

?>

[spiderwell]

all that does is check the bad words array , not the string.

[3raser]

all that does is check the bad words array , not the string.

 

Just fixed it as you posted.

[spiderwell]

hehe cool, i would offer up a solution but am actually trying to work on a project.

[dadamssg87]

awesome, thanks fellas!

[spiderwell]

try this mate, no offence to other poster, but I can't see that snippet working, or maybe I am just going mad:

<?php
$i = 0;
                $words = array('ass','fuck','shit');
$string = 'Blah blah blah ass blah blah fuck blah blah shit!';
foreach ($words as $value) 
{
                                 if (strpos($string,$value))
	{
		$i ++;		
                                 }
                 if($i>3) echo "naughty words limit";	
}
?>

 

[spiderwell]

actually that is flawed too, give me a few more mins, haha

[spiderwell]

this should do the trick, the mistake i made was with instr() it didnt count number of times a rude word might appear, so was looking for 3 different rude words, rather than a total of 3 rude words, be they all different or the same.

 

EDIT*** i should be shot for skim reading, this allows you to have 2 rude words and not more, really as soon as you get a hit of 1 curse word you want it to stop. i will post YET A?NOTHER solution haha i think i need to go to bed!! ******

 

<?php
$i = 0;
$limit = false;
$words = array('ass','fuck','shit');
$string = 'ass ass blah blah ass blah blah shit  blah ass!';
foreach ($words as $value) 	{
$i += substr_count($string,$value);// includes multiple counts of the same naughty word
if($i>=3)
	{
		$limit = true;
		echo "naughty word limit";
	}
if ($limit)break;// stops the search going any further
}	
?>

[spiderwell]

3rd time lucky (god i hope so!)

<?php

$words = array('ass','fuck','shit');
$string = 'Blah blah blah ass blah blah fuck blah blah shit!';	
foreach ($words as $value) 	
{	                                 
if (strpos($string,$value))
	{			
		echo "naughty words limit";
		break;
	}                 

}	
?>	

[3raser]

Didn't see post above. I recommend using his way, less code.

 

Tested, and works.

 

<?php

//bad words 0 1 2
$words = array('asshhfghh', 'gfhfghfgh', 'fuck');

//string to search
$string = 'Blah blah blah ass blah blah fuck blah blah shit!';

//amount in the array
$x = count($words) + 1;

while($i < $x)
{
	if(strpos($string, $words[$i]) === false)
	{
		++$i;
	}
	else
	{
		//holds the number of bad words found
		++$b;
		++$i;

	}
}

if(!$b)
{
	echo "No bad words found, yippe!";
}
else
{
	echo "Bad words found.";
}

?>	

[spiderwell]

yeah what confused me most was that I thought a count was necessary, when really its a sort of boolean search, there either is or isnt a curse word, one instance will make it true.

 

thats why my final snippet was much shorter, as no counting was involved

[dadamssg87]

hmm..i tried to implement this code

 

<?php
$words = array( 'fuck','shit', 'dick', 'cunt', 'twat', 'motherfucker', 'asshole', 'damn', 'bitch', 'bitching', 'fucking', 'fuckin', 'shitting', 'shittin', 'whore', 'whores', 'slut', 'sluts', 'bullshit', 'ass', 'bitches');


//string to search

$string = $sentence;

//amount in the array

$x = count($words) + 1;

while($i < $x)
{
if(strpos($string, $words[$i]) === false)
{
++$i;
}
else
{
//holds the number of bad words found
++$b;
++$i;
}
}


if(!$b)
{
//echo "No bad words found, yippe!";
}
else
{
	$_SESSION['message'] = "Your sentence contains curse words. Please remove the foul language.";
	die(header("location: test.php"));
}

 

but it doesn't count them as individual words. For example "I want to go bass fishing" will throw an error for the word "bass" because "ass" is in it. Any ideas how to make it only search for words? It doesn't seem to work if i just put spaces around the words in the array.

[3raser]

<?php
$words = array( 'fuck','shit', 'dick', 'cunt', 'twat', 'motherfucker', 'asshole', 'damn', 'bitch', 'bitching', 'fucking', 'fuckin', 'shitting', 'shittin', 'whore', 'whores', 'slut', 'sluts', 'bullshit', 'ass', 'bitches');

//string to search

$string = $sentence;

//amount in the array

$x = count($words);

for($i = 0; $i < $x; ++$i)
{
if(strpos($string, $words[$i]) === false)
{
++$i;
}
else
{
//holds the number of bad words found
++$b;
++$i;
}
}


if(!$b)
{
//echo "No bad words found, yippe!";
}
else
{
	$_SESSION['message'] = "Your sentence contains curse words. Please remove the foul language.";
	die(header("location: test.php"));
}
?>

 

This will count them as individual words.