col_edinburgh Posted April 8, 2011 Share Posted April 8, 2011 have a form with three list/menu items. Each one when selected acts a filter. I would like to submit the form when the user changes the value on each list.menu: I have tried adding an onchange="this.form.submit()" command on each list/menu but only the first one works. I guess the form only recognises one submit item. Is there a way to get the form to submit on each of the three list/menu items ? Many thanks, code ... <body> <form id="form1" name="form1" method="post" action=""> <label>Team <select name="myTeam" id="myTeam" onchange="this.form.submit()"> <?php do { ?> <option value="<?php echo $row_myTeam['title']?>"<?php if (!(strcmp($row_myTeam['title'], $_POST['myTeam']))) {echo "selected=\"selected\"";} ?>><?php echo $row_myTeam['title']?></option> <?php } while ($row_myTeam = mysql_fetch_assoc($myTeam)); $rows = mysql_num_rows($myTeam); if($rows > 0) { mysql_data_seek($myTeam, 0); $row_myTeam = mysql_fetch_assoc($myTeam); } ?> </select> </label> <label>Qct <select name="myQCT" id="myQCT" onchange="this.form.submit()"> <?php do { ?> <option value="<?php echo $row_chooseQCT['name']?>"<?php if (!(strcmp($row_chooseQCT['name'], $_POST['myQCT']))) {echo "selected=\"selected\"";} ?>><?php echo $row_chooseQCT['name']?></option> <?php } while ($row_chooseQCT = mysql_fetch_assoc($chooseQCT)); $rows = mysql_num_rows($chooseQCT); if($rows > 0) { mysql_data_seek($chooseQCT, 0); $row_chooseQCT = mysql_fetch_assoc($chooseQCT); } ?> </select> </label> <label>Year <select name="myYear" id="myYear" onchange="this.form.submit()"> <?php do { ?> <option value="<?php echo $row_myYear['year']?>"<?php if (!(strcmp($row_myYear['year'], $_POST['myYear']))) {echo "selected=\"selected\"";} ?>><?php echo $row_myYear['year']?></option> <?php } while ($row_myYear = mysql_fetch_assoc($myYear)); $rows = mysql_num_rows($myYear); if($rows > 0) { mysql_data_seek($myYear, 0); $row_myYear = mysql_fetch_assoc($myYear); } ?> </select> </label> </form> </body> Quote Link to comment Share on other sites More sharing options...
BlueSkyIS Posted April 8, 2011 Share Posted April 8, 2011 you're doing it the right way, using onchange. do you get any javascript errors? instead of posting the pre-compiled code, you might want to post the HTML output so we can see if there is a problem. Quote Link to comment Share on other sites More sharing options...
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