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Check if in array but not include some values in the array


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I have an array created to control the down states of the my buttons in my navigation. Which is working well. This array will have quite a few strings in it before I'm done.


I then want to conditionally load a CSS file for all the files in that array with the exception of two, is this possible?


In plain in english I want to say If in array apart from these values then load my css file.


My array (will have more values when complete)


$otherTitles = array('Product Selector', 'Avon Range', 'Knightsbridge Range', 'Kingston Range' );


My code to load a css file


<?php if (in_array($title, $otherTitles)) { ?>
<link rel="stylesheet" type="text/css" href="homepage.css"/>
<?php } ?>


I want all titles in the otherTitles array to get this CSS file apart from two Product Selector and Avon Range.






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If I understand what you're asking, you could just use a nested if statement. Something like:


<?php if (in_array($title, $otherTitles)): ?>
    <?php if ($title != 'Product Selector' && $title != 'Avon Range'): ?>
	<link rel="stylesheet" type="text/css" href="homepage.css"/>
<?php endif; ?>
<?php endif; ?>

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That's exactly what I meant thanks very much. Its only a small CSS anyway but not point in loading it if it doesn't need to be loaded.


Didn't know you could do nested statements like this (obviously)


Thanks very much!

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