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PHP code change MySQL to SQL

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#1 Fearpig

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Posted 09 October 2006 - 11:08 AM

Hi Guys,
I'm tring to change my code from a MySQL database to an SQL database. The code below should list the members of each department under the department heading. The first block works fine and outputs in the format that I want... the second one just lists the name of the first department 12 times (there are 13 departments in total if that helps).

Working MySQL.

$result = mysql_query("SELECT * FROM tbl_department",$db);
$subresult = mysql_query("SELECT * FROM tbl_telephonenumbers",$db);

while ($row = mysql_fetch_array($result)) {

	echo "<table width='250' border=0 class='Body2'>\n";

    printf("<tr><td align=center bgcolor=#CCCCCC><b class='Body2'>%s</b></td></tr>", $row["Department"]);
    $subresult = mysql_query("SELECT * FROM tbl_telephonenumbers",$db);
	echo "</table>";
	echo "<table width='250' border=0 class='Body2'>\n";	

	while ($row2 = mysql_fetch_array($subresult)) {
        if ($row['ID'] == $row2['Department']) {
            printf("<tr><td width='150'>%s %s</td>
			<td width='50'>%s</td>
			<td width='50'>%s</td></tr>", 
			$row2["First_Name"], $row2["Last_Name"], $row2["DDI"], $row2["Mobile_SD"]);
	echo "</table>\n";
    echo '<br><br>';

Broken SQL.

$sql="SELECT * FROM tbl_department";
if (!$result)
       {exit("Error in SQL");}

while (odbc_fetch_row($result)) 

		echo "<table>\n";
		echo "<tr><td><b class='Body2'>$Department_Name</b></td></tr>";
		$sub_sql="SELECT * FROM qry_Full_Employee_Details";
		if (!$subresult)
		       {exit("Error in SQL");}

		while (odbc_fetch_row($subresult)) 
        		                          if ($DeptID == $Department) 
						echo "<tr><td>$First_Name $Last_Name</td></tr>"; 
		echo "</table>\n";
    	             echo '<br><br>';

Can anyone see where the problem is? Any help would be appreciated.

"Whats wrong with the cat?" - Mrs Schrödinger

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