oriental_express Posted April 21, 2011 Share Posted April 21, 2011 Hi I've got this database I created with fields ProductId ProductName Image I've managed to get it to list the ID,productname, and Image urls in a list. My next step is to have the image field actually display an image and make it clickable: heres what I've done so far: <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("productfeed", $con); $result = mysql_query("SELECT * FROM productfeeds"); echo "<table border='0'> <tr> <th>Firstname</th> <th>Lastname</th> <th>Image</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; echo "<td>" . $row['ImageURL'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Heres what I want to do: while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; // my changes beneath echo "<td>" . <a href="<?php echo $row['ImageURL'];?>"> <img src="<?php echo $row['LinkURL']; ?>"> </a>. "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Can you guys point me in the right direction? Many thanks Quote Link to comment https://forums.phpfreaks.com/topic/234350-tyring-to-create-an-image-link-where-source-url-and-link-is-in-database/ Share on other sites More sharing options...
Muddy_Funster Posted April 21, 2011 Share Posted April 21, 2011 where are you getting $row['LinkURL'] from? Quote Link to comment https://forums.phpfreaks.com/topic/234350-tyring-to-create-an-image-link-where-source-url-and-link-is-in-database/#findComment-1204486 Share on other sites More sharing options...
oriental_express Posted April 21, 2011 Author Share Posted April 21, 2011 where are you getting $row['LinkURL'] from? Hi there I'm not sure I suppose what I'm trying to do with LinkURL is to make the image clickable? All other areas has $rows so I thought I would try it. is it possible to have a href link inbetween an echo function? Where am I going wrong ? Quote Link to comment https://forums.phpfreaks.com/topic/234350-tyring-to-create-an-image-link-where-source-url-and-link-is-in-database/#findComment-1204488 Share on other sites More sharing options...
Muddy_Funster Posted April 21, 2011 Share Posted April 21, 2011 if it is the full URL for the immage that is stored in the database then all you need is: echo "<td><a href='{$row['ImageURL']}'> <img src='{$row['ImageURL']}'> </a></td>"; this will take you to the image, replace the value for href= if you want to go some place else. Quote Link to comment https://forums.phpfreaks.com/topic/234350-tyring-to-create-an-image-link-where-source-url-and-link-is-in-database/#findComment-1204491 Share on other sites More sharing options...
oriental_express Posted April 21, 2011 Author Share Posted April 21, 2011 if it is the full URL for the immage that is stored in the database then all you need is: echo "<td><a href='{$row['ImageURL']}'> <img src='{$row['ImageURL']}'> </a></td>"; this will take you to the image, replace the value for href= if you want to go some place else. Thank you very much It now works. Quote Link to comment https://forums.phpfreaks.com/topic/234350-tyring-to-create-an-image-link-where-source-url-and-link-is-in-database/#findComment-1204494 Share on other sites More sharing options...
Muddy_Funster Posted April 21, 2011 Share Posted April 21, 2011 you are very welcome Quote Link to comment https://forums.phpfreaks.com/topic/234350-tyring-to-create-an-image-link-where-source-url-and-link-is-in-database/#findComment-1204497 Share on other sites More sharing options...
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