How to get syntax right for a file name

[HuntsvilleMan]

I'm unsure what to put in the path statement below.  My attemps so far end up in an error message.

 

Here is what I know:

    The company that host my files has me at a web address like: mycompany6.com

    In that root directory I have a subdirectory named: php

    In that subdirectory I have a file named: testfile.mp3

 

Getting the path statement right seems to be my problem.  Below is my last failed try.

 

      $file = "testfile.mp3";

      $path = $_SERVER['mycompany6.com']."/php/";

      $file = $path.$filename;

      $file_size = filesize($file);

      echo $file_size;

 

Do I have enough information to complete the path statement or do

I need another piece of information from my web hosting service?

 

Thanks for an explanation of how to get the path statement right.

 

Mike

[spiderwell]

have you echoed out $path to see what it says?

where is the php file that is doing this located?

[fugix]

have you tried

 $file = "testfile.mp3";
      $path = http://www.mycompany6.com/php/;
      $file = {$path}{$filename};
      $file_size = filesize($file);
      echo $file_size;

[jcbones]

Make a simple file in the directory of the file you wish to get the size of, and call it from the browser.

test.php

<?php 
echo __FILE__;
?>

 

Then copy that as the file path.  Of course, change the filename at the end to the correct filename.

 

This is the easiest method that I can think of, that will give YOU the filepath of your file.  Otherwise, you could try all day with suggestions.

 

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