drayarms Posted May 12, 2011 Share Posted May 12, 2011 I had posted a similar post a few days back, about an display script which is supposed to retrieve a stored image from my database and displays it on an html page, but fails to do so. Someone suggested that I upload my image onto a folder on the server and then save the image path name in my database. I found this script(below) which does just that. It uploads the image into a folder on the server called images and stores the image path into a table in my database called images and I know this script works because i saw the file saved in the images folder and the path name inserted into the images table. <?php //This file inserts the main image into the images table. //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //authenticate user //Start session session_start(); //Connect to database require ('config.php'); //Check whether the session variable id is present or not. If not, deny access. if(!isset($_SESSION['id']) || (trim($_SESSION['id']) == '')) { header("location: access_denied.php"); exit(); } else{ // Check to see if the type of file uploaded is a valid image type function is_valid_type($file) { // This is an array that holds all the valid image MIME types $valid_types = array("image/jpg", "image/jpeg", "image/bmp", "image/gif"); if (in_array($file['type'], $valid_types)) return 1; return 0; } // Just a short function that prints out the contents of an array in a manner that's easy to read // I used this function during debugging but it serves no purpose at run time for this example function showContents($array) { echo "<pre>"; print_r($array); echo "</pre>"; } // Set some constants // This variable is the path to the image folder where all the images are going to be stored // Note that there is a trailing forward slash $TARGET_PATH = "images/"; // Get our POSTed variable $image = $_FILES['image']; // Sanitize our input $image['name'] = mysql_real_escape_string($image['name']); // Build our target path full string. This is where the file will be moved to // i.e. images/picture.jpg $TARGET_PATH .= $image['name']; // Make sure all the fields from the form have inputs if ( $image['name'] == "" ) { $_SESSION['error'] = "All fields are required"; header("Location: member.php"); exit; } // Check to make sure that our file is actually an image // You check the file type instead of the extension because the extension can easily be faked if (!is_valid_type($image)) { $_SESSION['error'] = "You must upload a jpeg, gif, or bmp"; header("Location: member.php"); exit; } // Here we check to see if a file with that name already exists // You could get past filename problems by appending a timestamp to the filename and then continuing if (file_exists($TARGET_PATH)) { $_SESSION['error'] = "A file with that name already exists"; header("Location: member.php"); exit; } // Lets attempt to move the file from its temporary directory to its new home if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); header("Location: images.php"); echo "File uploaded"; exit; } else { // A common cause of file moving failures is because of bad permissions on the directory attempting to be written to // Make sure you chmod the directory to be writeable $_SESSION['error'] = "Could not upload file. Check read/write persmissions on the directory"; header("Location: member.php"); exit; } } //End of if session variable id is not present. ?> Now the display image script accompanying this insert image script is shown below. <?php // Get our database connector require("config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Dream in code tutorial - List of Images</title> </head> <body> <div> <?php // Grab the data from our people table $sql = "SELECT * from images WHERE image_cartegory = 'main'"; $result = mysql_query($sql) or die ("Could not access DB: " . mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo "<div class=\"picture\">"; echo "<p>"; // Note that we are building our src string using the filename from the database echo "<img src=\"images/ " . $row['filename'] . " \" alt=\"\" />"; echo "</p>"; echo "</div>"; } ?> </div> </body> </html> Well, needless mentioning, the picture isn't displayed. Just a tiny jpeg icon is displayed at the top left hand corner of the page. Figuring out that the problem might be the lack of a header that declares the image type, I add this line header("Content-type: image/jpeg"); but all it does is display a blank white page, without the tiny icon this time. What am I missing? Any clues?? Quote Link to comment https://forums.phpfreaks.com/topic/236199-image-display-script-problem/ Share on other sites More sharing options...
hyster Posted May 12, 2011 Share Posted May 12, 2011 are u getting an image place holder? ie the red square with an x in it. if so right click in the square n select properties. you will see the url where the image is supposed to be. quick test is copy the url into the browser hit enter and see if it display's if not check the url to see if its correct to where ur images are stored. Quote Link to comment https://forums.phpfreaks.com/topic/236199-image-display-script-problem/#findComment-1214405 Share on other sites More sharing options...
drayarms Posted May 12, 2011 Author Share Posted May 12, 2011 @hyster ok i followed your advice. the image url is as follows www.mysite.com/images so it actually points to the folder (images) where i store my pictures on the server but doesn't point to the filename. any idea why this may be the case? Quote Link to comment https://forums.phpfreaks.com/topic/236199-image-display-script-problem/#findComment-1214649 Share on other sites More sharing options...
drayarms Posted May 12, 2011 Author Share Posted May 12, 2011 ok folks, thanks to a lead from hyster, i discovered that the problems lay in this particular line echo "<img src=\"images/ " . $row['filename'] . " \" alt=\"\" />"; First of all, there can't be any white space between the escape character / and the " Secondly, I forgot to change ['filename'] to ['image'] The scripts works fine, and I'd reccomend it to anyone. Quote Link to comment https://forums.phpfreaks.com/topic/236199-image-display-script-problem/#findComment-1214667 Share on other sites More sharing options...
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